The solution to the problem is as follows:
let
R = $619.15 periodic payment
i = 0.0676/12 the rate per month
n = 48 periods
S = the future value of an ordinary annuity
S = R[((1 + i)^n - 1)/i]
S = 619.15*[(1 + 0.0676/12)^48 - 1)/(0.0676/12)]
S = $34,015.99
I hope my answer has come to your help. God bless and have a nice day ahead!
I cant see the numerators on the numbers on the top one but the last one is 53/60.
Hello! :)
The <u>answer</u> is x+15!
~Hope it helps!~ :)
This involves quite a lot of arithmetic to do manually.
The first thing you do is to make the first number in row 2 = to 0.
This is done by R2 = -3/2 R1 + R2
so the matrix becomes
( 2 1 1) ( -3 )
( 0 -13/2 3/2) (1/2 )
(5 -1 2) (-2)
Next step is to make the 5 in row 5 = 0
then the -1 must become zero
You aim for the form
( 1 0 0) (x)
(0 1 0) (y)
(0 0 1) ( z)
x , y and z will be the required solutions.
