A rectagular, above ground pool is 18 feet long, 9 feet wide, and 54 inches deep. One cubic foot of water weighs about 62.4 poun

Question

3 years ago

15

ds. What is the total weight of the water in the pool when it is completely full?

1 answer:

ollegr [7] · Answer 1 · 2022-04-30T02:24:28+03:00

Answer:

45,489.6 pounds!

Step-by-step explanation:

To solve this problem, first we need to find the volume of the pool.

We know that the dimensions of the pool are:

Width = 9ft

Length = 18ft

Height = 54in = 4.5 ft

So the volume of the pool is:

Volume = Width x Length x Height = 9ftx18ftx4.5ft = 729ft^3

We know that one cubic foot of water weights about 62.4 pounds. To fill the pool, we will need 729ft^3 of water.

So the weight of the water is:

Weight = 729ft^3 x 62.4 pounds/ft = 45,489.6 pounds!