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a_sh-v [17]
3 years ago
15

A rectagular, above ground pool is 18 feet long, 9 feet wide, and 54 inches deep. One cubic foot of water weighs about 62.4 poun

ds. What is the total weight of the water in the pool when it is completely full?
Mathematics
1 answer:
ollegr [7]3 years ago
4 0

Answer:

45,489.6 pounds!

Step-by-step explanation:

To solve this problem, first we need to find the volume of the pool.

We know that the dimensions of the pool are:

Width = 9ft

Length = 18ft

Height = 54in = 4.5 ft

So the volume of the pool is:

Volume = Width x Length x Height = 9ftx18ftx4.5ft = 729ft^3

We know that one cubic foot of water weights about 62.4 pounds. To fill the  pool, we will need 729ft^3 of water.

So the weight of the water is:

Weight = 729ft^3 x 62.4 pounds/ft = 45,489.6 pounds!

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Algebraic equation of 185 is less than a number
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Answer:

n-185

Step-by-step explanation:

since 185 needs to be subtracted from a number, or n

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2 years ago
I need help.........................
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Step-by-step explanation:

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2 years ago
PLZ help on 1 and 2 ASAP have to turn in homework now.
dezoksy [38]
<h2>1.</h2>
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3 0
3 years ago
What does x equal in -7=-1+x/3
Scorpion4ik [409]

Hello! :)

To solve your equation, we will first simplify both sides of the equation

-7 = -1 + x/3

-7 = -1 + 1/3x

-7 = 1/3x - 1

Next, we will flip the equation

1/3x - 1 = -7

Third, we will add 1 to both sides

1/3x - 1 + 1 = -7 + 1

1/3x = -6

Last, we will Multiply both sides by 3

3 * (1/3x) = (3) * (-6)

x = -18 (ANSWER)

That means -18 is you answer

Hope this helped you!

THEDIPER

3 0
3 years ago
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