Step-by-step explanation:
(4/5+3/5)+3.5*5
= 7/5+7/2*5
= 7/5+35/2
= 14/10+175/10
= 189/10
= 18.9
Answer:
Kayla plays on average 0.2 more chess games than Becker
Step-by-step explanation:
The first thing we must do is calculate the mean of each one.
Becker:
(5 + 2 + 4 + 1 + 1 + 4 + 5 + 3 + 2 + 1) / 10 = 2.8
Kayla:
(2 + 3 + 1 + 1 + 4 + 1 + 5 + 3 + 5 + 5) / 10 = 3
if we subtract these averages, we have to:
3 - 2.8 = 0.2
which means that Kayla plays on average 0.2 more chess games than Becker. Since it is not even a complete game, the difference between the two is very small and almost irrelevant.
Answer:
Kevin's estimate is incorrect. When x=4, the value of y is $116, which is not close to
$180.
Step-by-step explanation:
. x + (x + 2)≤166
. 2x+2≤166
. x≤83 - 1
. x≤82
. x=81
. 81+(81+2)=164; 164<166
answer: 81 and 83
Answer:
193 mg
Step-by-step explanation:
Exponential decay formula:

- where Aₜ = mass at time t, A₀ = mass at time 0, r = decay constant (rate), t = time
Our known variables are:
- 1998 to the year 2004 is a total of t = 6 years.
- The sample of radioactive isotope has an initial mass of A₀ = 360 mg at time 0 and a mass of Aₜ = 270 mg at time t.
Let's solve for the decay constant of this sample.
Using our new variables, we can now solve for Aₜ at t = 7 years, since we go from 2004 to 2011.
Our new initial mass is A₀ = 270 mg. We solved for the decay constant, r = 0.04794701.
The expected mass of the sample in the year 2011 would be 193 mg.