Answer:
141000 * (1 - 0.016)^15 = 110699.48 = A 110700
Step-by-step explanation:
1st year depreciation = 141000 - (141000 * 0.016) = 138744
2nd year depreciation = 138744 - (138744 * 0.016) = 136524.096
3rd year depreciation = 136524.096 - (136524.096 * 0.016) = 134339.710464
etc. unitl you reach the 15th year
Basically we calculate 1.6% of the current value of the house and subtract that from the current value for each year for 15 years.
The equation used in the answer is a faster way to approach your answer instead of calculating for each year.
You'd multiply your initial value by the difference in percentage (note well that since it is decreasing in value we subtract the decimal equivalent to 1.6% which is 0.016, from 1 where one represents 100% and then raise the difference gained to the power of the amount of years which would be 15.
Y = -x + 3 .… m = -1
y = 2x – 6 .… m = 2
Tan Ø = | m2 – m1 / 1 + m2m1 |
Tan Ø = | 2 – -1 / 1 + (2 x -1) |
Tan Ø = | 3 / -1 |
Tan Ø = | -3 |
Tan Ø = 3
Ø = tan^-1 ( 3 )
Ø = 71.5°
The answer fam is....... 3x - 10
416.67 pounds of food should be given all five lions each day
<em><u>Solution:</u></em>
Given that, three adult lions together eat 250 pounds of food a day
Thus, 3 adult lions = 250 pounds of food per day
Two more adult lions joined the group and ate food at the same rate as the original three
Now number of adult lions = 3 adult lions + 2 adult lions = 5 adult lions
Let "x" be the food ate by 5 adult lions
Thus we can say,
3 adult lions = 250 pounds of food per day
5 adult lions = "x" pounds of food per day
This forms a proportion and we can solve the sum by cross multiplying
Thus 416.67 pounds of food should be given all five lions each day
<span><span>(<span>6−d</span>)</span><span>(<span><span><span>d^2</span>−5</span>+<span>3d</span></span>)</span></span><span>=<span><span>(<span>6+<span>−d</span></span>)</span><span>(<span><span><span>d^2</span>+<span>−5</span></span>+<span>3d</span></span>)</span></span></span><span>=<span><span><span><span><span><span><span>(6)</span><span>(<span>d^2</span>)</span></span>+<span><span>(6)</span><span>(<span>−5</span>)</span></span></span>+<span><span>(6)</span><span>(<span>3d</span>)</span></span></span>+<span><span>(<span>−d</span>)</span><span>(<span>d^2</span>)</span></span></span>+<span><span>(<span>−d</span>)</span><span>(<span>−5</span>)</span></span></span>+<span><span>(<span>−d</span>)</span><span>(<span>3d</span>)</span></span></span></span><span>=<span><span><span><span><span><span>6<span>d^2</span></span>−30</span>+<span>18d</span></span>−<span>d^3</span></span>+<span>5d</span></span>−<span>3<span>d^2</span></span></span></span><span>
=<span><span><span><span> −<span>d3^</span></span>+<span>3<span>d^2</span></span></span>+<span>23d</span></span>−<span>30</span></span></span>
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