Answer:
<u>Demographic</u>
Explanation:
Harry's caters to the clothing needs of men, manufacturing two different lines of fashion based on the purchasing power of its customer . One product line caters to the needs pf affluent , middle-aged men , and the other line targets younger , up -and - coming professionals . Harry's most likely segments the consumer market is based on<em><u> demographic variables.</u></em>
<em>The statistical data of the population of the people is known as demographics . Demographics contain age , gender , income etc.</em>
Demographic is important for the company as it help the company to tell about how to market and how to develop the brand. It helps in telling the behavior of the customer towards the product means whether the people liking the product or not liking the product . It is consider as the best way to reach to the people and know about their preference for the product.
Answer: True
Explanation: Cumulative preferred shares of a company carries some special rights as per law. The holders of such stock must be paid any current or prior period accrued dividends before any payment of dividend to common shareholders. The dividends of such shareholders is fixed in nature.
Also in the event of liquidation they will be preferred before any common stock holders.
Thus, the given statement is true.
Answer:
Syndicated Data
Explanation:
Syndicated is a general data which does not represents a single entity, it includes a vast number of entities data that is aggregated to analyze how much value the company can drive from this aggregate amount. So the data that helps in analyzing the environment in general to plan the future move of organization is known as Syndicated Data. The manager is collecting aggregate data that comes from a wide number of bands, including industry sales by musical styles, online views, etc. is a syndicated data.
Complete Question:
The project represented by this resource load chart (see attached) has a maximum limit of 6 units of resource activity in any day. The first activities that are strong candidates for shifting are:
A) Activity A
B) Activities B and C
C) Activities D and E
D) Activity E and F
Answer:
The first activities that are strong candidates for shifting are:
C) Activities D and E
Explanation:
Activities D and E have a total time of 5 days altogether based on the attached resource load chart. They have the least time and can be shifted to accommodate other activities before they can be tackled sequentially.
A resource load chart displays the total amount of resources required as a function of time in any given project. It is the best method for establishing the existence of some resource conflicts across project activities, especially when compared to Gantt Charts, Network Diagrams, and Pareto Diagrams.
Answer:
a-The present value of revenue in the first year is $61,085.92.
b-The total time it would take to pay for its price is 2.44 years of 29.33 months.
Explanation:
a-
Let the function of the revenue earned is given as
![S(t)=\left \{ {{66000t+38000} {\ \ 0The present value is given as [tex]PV=\int\limits^a_b {S(t)e^{-rt}} \, dt](https://tex.z-dn.net/?f=S%28t%29%3D%5Cleft%20%5C%7B%20%7B%7B66000t%2B38000%7D%20%7B%5C%20%5C%200%3C%2Fp%3E%3Cp%3EThe%20present%20value%20is%20given%20as%20%3C%2Fp%3E%3Cp%3E%5Btex%5DPV%3D%5Cint%5Climits%5Ea_b%20%7BS%28t%29e%5E%7B-rt%7D%7D%20%5C%2C%20dt)
Here
- a and b are the limits of integral which are 0 and 1 respectively
- r is the rate of interest which is 5% or 0.05
- S(t) is the function of value which is
![S(t)=\left \{ {{66000t+38000} {\ \ 0So the equation becomes[tex]PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t+38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t)e^{-0.05t}} \, dt+\int\limits^{0.5}_0 {(38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=8113.7805+18764.4669+34207.6751\\PV=61085.9225](https://tex.z-dn.net/?f=S%28t%29%3D%5Cleft%20%5C%7B%20%7B%7B66000t%2B38000%7D%20%7B%5C%20%5C%200%3C%2Fli%3E%3C%2Ful%3E%3Cp%3ESo%20the%20equation%20becomes%3C%2Fp%3E%3Cp%3E%5Btex%5DPV%3D%5Cint%5Climits%5E0_1%20%7BS%28t%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2866000t%2B38000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B1%7D_%7B0.5%7D%7B%2871000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2866000t%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2838000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B1%7D_%7B0.5%7D%7B%2871000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D8113.7805%2B18764.4669%2B34207.6751%5C%5CPV%3D61085.9225)
So the present value of revenue in the first year is $61,085.92.
b-
The time in which the machine pays for itself is given as

The present value is set equal to the value of machine which is given as
$160,000 so the equation becomes:

So the total time it would take to pay for its price is 2.44 years of 29.33 months.