Given Information:
Population mean = p = 60% = 0.60
Population size = N = 7400
Sample size = n = 50
Required Information:
Sample mean = μ = ?
standard deviation = σ = ?
Answer:
Sample mean = μ = 0.60
standard deviation = σ = 0.069
Step-by-step explanation:
We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10
np ≥ 10
50*0.60 ≥ 10
30 ≥ 10 (satisfied)
n(1 - p) ≥ 10
50(1 - 0.60) ≥ 10
50(0.40) ≥ 10
20 ≥ 10 (satisfied)
The mean of the sampling distribution will be same as population mean that is
Sample mean = p = μ = 0.60
The standard deviation for this sampling distribution is given by

Where p is the population mean that is proportion of female students and n is the sample size.

Therefore, the standard deviation of the sampling distribution is 0.069.
5(x+y)= 20+ 3x
5x+5y=20+3x
5x+5y-3x=20+3x-3x
2x+5y=20
2x+5y-2x=20-2x
5y=-2x+20
5y/5=-2x/5+20/5
y=-2/5x+4
ANSWER: y=-2/5x+4
Normalmente, el fracaso se asocia con el valor 0 y el éxito con el 1. Se nombra como Be(p), donde p(X=1) = p es la probabilidad de obtener éxito y p(X=0) = q = 1-p la probabilidad obtener fracaso.
Answer:
31.43ft
Step-by-step explanation:
πd=22/7×10ft
=31.43ft