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alexandr402 [8]
3 years ago
7

Solve (3x) 9 = (4x) 5

Mathematics
1 answer:
Leto [7]3 years ago
6 0

Answer:

4 = 1x

Step-by-step explanation:

(3x)9 = (4x)5

9 = (1x) 5

4 = 1x

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4*4=16+7=23

Step-by-step explanation:

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Step-by-step explanation:

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7 0
3 years ago
Help ASAP going school soon
katen-ka-za [31]
Answers:
____________________________________
<span>
Angle B:  81°</span> .
____________________________________
<span>
Angle C:  99°</span> .
____________________________________
<span>
Angle D:  81°</span> .
_____________________________________________
<span>
Explanation:</span>
_______________________________________________________
<span>
Angle B:</span>
_______________________________________________________
Given:  m∡A = 99° ;

 ∡A and ∡B are "supplementary angles" ;
                          and supplementary angles add up to 180°.
_______________________________________________________
<span>      → So, m∡B = 180 − 99 = 81° </span>.
_______________________________________________________
Angle C:  99° .
_______________________________________________________
Explanation:
_______________________________________________________
 Given:  m∡A = 99° .

 ∡A and ∡C are "vertical angles".  Vertical angles are congruent.
______________________________________________________
   → So m∡A = m∡C = 99° .
______________________________________________________
Angle D:  81° .
______________________________________________________
Explanation:
______________________________________________________
   ∡B and ∡D are vertical angles.  Vertical angles are congruent.
    
    As previously determined above,  m∡B = 81° .
______________________________________________________
     → So, m∡D = m∡B = 81° .
<span>______________________________________________________</span>
7 0
3 years ago
Complex numbers zj and zz are given by zj = 3- j2, zz = - 4 + j3. (a) express zj and zz in polar form. (b) find lz1l by first ap
inna [77]

Solution:

Given: zj = 3- j2, zz = - 4 + j3

Part a:

zj = 3- j2 = 3.6e^{-j33.7^{\circ}}

zz = - 4 + j3 = 5e^{j143.1^{\circ}}

Part b:

|zj| = |3− j2| =  √3² +(−2)² = √13 = 3.60

|z1| =  √(3− j2)(3+ j2) = √ 13 = 3.60.

Part c:

With the help of part a:

z1z2 = 3.6e^{-j33.7^{\circ}}.5e^{j143.1^{\circ}}

6 0
3 years ago
Draw four more rectangles with areas equal to 24cm².​
max2010maxim [7]
Area of rectangle is equal to: length times width. A=l•w
If A=24cm^2
24cm^2=1cm•24cm
24cm^2=2cm•12cm
24cm^2=3cm•8cm
24cm^2=4cm•6cm
Good luck
7 0
3 years ago
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