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3 years ago

11) Krystal and Rob each improved their yards by planting hostas and ivy. They bought their

Mathematics

1 answer:

umka2103 [35]3 years ago

3 0

Answer: Cost of one hosta = $11

Cost of one pot of ivy = $11

Step-by-step explanation:

Let the the cost of one hosta be represented by x.

Let the cost of one pot of ivy be represented by y.

The information given in the question can be formed into an equation as:

8x + 4y = 132 ............ i

2x + 2y = 44 ............. ii

Multiply equation i by 2

Multiply equation ii by 4

16x + 8y = 264 ........ iii

8x + 8y = 176 ........ iv

Subtract iv from iii

8x = 88

x = 88/8

x = 11

One hosta cost $11

From equation ii

2x + 2y = 44

2(11) + 2y = 44

22 + 2y = 44

2y = 44 - 22

2y = 22

y = 22/2

y = 11

One pot of ivy cost $11

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Fourth option: (-2,-4)

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4 years ago

Read 2 more answers

5. Based on recent results, scores on the SAT test are normally distributed with a mean of 1511 and a standard deviation of 312.

Mekhanik [1.2K]

Answer:

The actual SAT score is 2024.

The equivalent ACT score is 29.49.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

SAT score that is in the 95th percentile

Scores on the SAT test are normally distributed with a mean of 1511 and a standard deviation of 312, which means that $\mu = 1511, \sigma = 312$