Use Pythagorean theorem to solve.
a^2 + b^2 = c^2
6^2 + b ^2 = 14^2
36 + b^2 = 196
Subtract 36 from both sides.
b^2 = 196-36
b^2 = 160
Take the square root of both sides.
b = sqrt 160
As a decimal
b = 12.649
As a simplified radical
b = 4sqrt10
Answer:
I can't see anything or any questions.....?
AB - C2 = (x2)(3x + 2) - (x-3)2
AB - C2 = 3x3 + 2x2 - (x2 -6x +9)
AB - C2 = = 3x3 + 2x2 - x2 + 6x - 9
AB - C2 = = 3x3 + x2 + 6x - 9
Answer:
6 and -14
Step-by-step explanation:
Area of the triangle = 1/2 ab
42 = 1/2 (x)(x+8)
42 *2 = x(x+8)
84 = x²+8x
x²+8x-84 = 0
x²+14x-6x-84 = 0
x(x+14)-6(x+14) = 0
x-6 = 0 and x+14 = 0
x = 6 and -14
Hence the values of x are 6 and -14
Answer:
pearls profs
Step-by-step explanation:
becuse i got the same qwestion and got it wrtei
