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babymother [125]
2 years ago
9

A particle is moving with the given data. Find the position of the particle. a(t) = t2 − 2t + 9, s(0) = 0, s(1) = 20

Mathematics
1 answer:
lozanna [386]2 years ago
6 0

Answer:

Position of the particle is 20.

Step-by-step explanation:

Position function is integration of velocity function.

Velocity function is integration of acceleration function.

So, let's integrate the given a(t) to get v(t)

If we integrate v(t) then we get s(t)

It is given the values of s(0) =0 and s(1)=20

So, position of the particle is difference of 20, 0. That's 20-0 =20.

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The midpoint of GH is M( 6,-4). One endpoint is G(8,-2). Find the coordinates of endpoint H.
Finger [1]

Using the midpoint formula, the coordinates of endpoint H are (4, -6).

<h3>The Midpoint Formula</h3>

The midpoint formula is given as: (x_m, y_m) = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} )

<em>Where</em>,

(x_m, y_m) = coordinates of the midpoint

(x_1, y_1) = coordinates of the first point

(x_2, y_2) = coordinates of the second point

Given the following:

(x_m, y_m) = M( 6,-4)

(x_1, y_1) = G(8,-2)

(x_2, y_2) = H(?, ?)

Plug in the values into the midpoint formula

M(6, -4) = (\frac{8 + x_2}{2}, \frac{-2 + y_2}{2} )

Solve for the x-coordinate and y-coordinate separately

6 = \frac{8 + x_2}{2}

  • Multiply both sides

6 \times 2 = 8 + x_2\\\\12 = 8 + x_2\\\\12 - 8 = x_2\\\\4 = x_2\\\\\mathbf{x_2 = 4}

-4 = \frac{-2 + y_2}{2}\\\\-8 = -2 + y_2\\\\-8 + 2 = y_2\\\\-6 = y_2\\\\\mathbf{y_2 = -6}

Therefore, using the midpoint formula, the coordinates of endpoint H are (4, -6).

Learn more about midpoint formula on:

brainly.com/question/13115533

3 0
2 years ago
PLEASE PLEASE PLEASE HELP!!
Tema [17]
My answer is use a map app like Photomath
8 0
3 years ago
5 +4.2 + 5 – 2. 2 - 1​
Liula [17]
14.2 - 2.2 - 1
12 -1
11

Hope this helps
7 0
3 years ago
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vladimir1956 [14]
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Year x: 500 [1 + 0.25]^x

Option d: A(x) = 500[1 + .25]^x, where .25 is the interest rate
5 0
3 years ago
When two computers are working together, they can finish updating software in 9 minutes. How long would they take individually t
tensa zangetsu [6.8K]
First computer takes x min. For 1 min it does 1/x part of work.

Second computer takes (x+24) min. For one min it does 1/(x+24) part of work.

Both computers for one min do   (1/x+1/(x+24)) part of work.

At the same time, both computers for one min do 1/9 part of work.

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7 0
3 years ago
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