We model the ticket as a rectangle.
For this case what you should know is that the perimeter of the rectangle is given by:
P = 2w + 2l
The area of the rectangle is given by:
A = w * l
In both cases:
w: width
l: long
We have the following system of equations:
32 = 2w + 2l
60 = w * l
Solving the system we obtain:
The dimensions of the ticket are:
(10 cm) * (6 cm)
Answer:
the dimensions of the ticket are:
(10 cm) * (6 cm)
Note: see attached image for system solution
For this case what you should know is that the perimeter of the rectangle is given by:
P = 2w + 2l
The area of the rectangle is given by:
A = w * l
In both cases:
w: width
l: long
We have the following system of equations:
32 = 2w + 2l
60 = w * l
Solving the system we obtain:
The dimensions of the ticket are:
(10 cm) * (6 cm)
Answer:
the dimensions of the ticket are:
(10 cm) * (6 cm)
Note: see attached image for system solution