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ankoles [38]
3 years ago
13

The diameter of circle Q is 14 cm. Find the arc length of PR.

Mathematics
1 answer:
mario62 [17]3 years ago
7 0

Answer:

4.15, or 1.32pi

Step-by-step explanation:

arclength is circumference(34/360)

so pi x d (34/360)

3.14 x 14 x (34/360) = 4.15, or 1.32pi

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Find the greatest common factor of 24, 64, 108.
Ainat [17]

Answer:

The answer is 4.

Step-by-step explanation:

To find the greatest common factor (GCF), start by listing the factors of each number.

For 24: 1, 2, 3, 4, 6, 8, 12, 24

For 64: 1, 2, 4, 8, 16, 32, 64

For 108: 1, 2, 3, 4, 6, 9, 12, 18

Since all the factors are now written out, we can find the greatest common factor between 24, 64, and 108, and the GCF is 4.

6 0
3 years ago
What’s is the solution to the equation x to the power of 2 =16/25
skelet666 [1.2K]

Answer:

x=\dfrac{4}{5}

Step-by-step explanation:

The given equation is :

x^2=\dfrac{16}{25}

We need to find the value of x.

When the exponent 2 removes from LHS, it will shift to RHS as square root as follows :

x=\sqrt{\dfrac{16}{25}}

We know that, 4×4= 16 and 5×5 = 25

So,

x=\sqrt{\dfrac{4\times 4}{5\times 5}}\\\\x=\dfrac{4}{5}

So, the solution of the given equation is 4/5.

4 0
3 years ago
Jack earns $50 for washing cars on the weekend. he makes an average of $4.25 in tips per hour. write the function of joe's earni
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3 years ago
What prompted (caused) Gandhi to begin a campaign of passive resistance in South Africa?
Firlakuza [10]

Answer:

Asiatic Registration Bill of 1906.

Step-by-step explanation:

The first passive resistance campaign was started in Johannesburg in 1907 with, and for, the wealthy South African Indian merchants whom he had so long represented.’ Gandhi’s first passive resistance campaign began as a protest against the Asiatic Registration Bill of 1906.

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2 years ago
These tables show equivalent ratios. The value missing in each table is replaced with X. Choose ALL tables in which 12 replaces
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Answer:

a

Step-by-step explanation:

3 0
3 years ago
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