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pishuonlain [190]
3 years ago
13

SOMEONE PLEASE HELP WITH MY MATH ON MY ACCOUNT PAGE

Mathematics
1 answer:
Ugo [173]3 years ago
8 0

Answer:

Ok! :)

Step-by-step explanation:

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Can someone please explain how I apply SOHCAHTOA properly to this?
liq [111]

Answer:

e

Step-by-step explanation:

4 0
3 years ago
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Please help me out please
N76 [4]
You can solve this since you can develop 3 equations for your 3 unknowns. Each equation is made using the Pythagorean theorem:

1) x^2 = y^2 + 16^2
2) z^2 = y^2 + 4^2
3) (16 + 4)^2 = z^2 + x^2

Simplifying the above we get:

1) x^2 = y^2 + 256
2) z^2 = y^2 + 16
3) 400 = z^2 + x^2

We want to solve for z. There are several ways but an easy one is with substitution. Start by rearranging 2) and 3) like this:

2’) y^2 = z^2 - 16
3’) x^2 = 400 - z^2

Now we have expressed x and y in terms of z. Plug these values into the unused equation, 1), to solve for z:

1’) 400 - z^2 = z^2 - 16 + 256
2z^2 = 160
z^2 = 80
z = √80
z = √(16)(5)
z = 4√5
3 0
4 years ago
- of a number is 27. What's the number?<br> k.
nikklg [1K]

Answer:

Three of those boxes equals 27, you would take 27/3 to find out that each box is worth 9. You now want to take 9*4 to get your total number

9*4=36

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Step-by-step explanation:

5 0
4 years ago
Solve for x: 2x – y = (3/4)x + 6.
Artyom0805 [142]

Answer:

B

Step-by-step explanation:

2x – y = (3/4)x + 6.

or, 2x - (3/4)x = y + 6.

or, (8x -3x)/4 = y + 6.

or, 5x/4 = y + 6.

or, 5x = 4(y + 6).

or, 5x = 4y + 24.

or, x = (4y + 24)/5.

Therefore, x = 4(y + 6)/5.

6 0
3 years ago
A tutor with a group of students. the tutor charges $40 plus $30 for each student in the group. Today the tutor has s students a
Bad White [126]

Answer: Is 3 Students.

Step-by-step explanation:  30+40=70   220/70=3.

So 3 students are in the group.


8 0
3 years ago
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