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3 years ago

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Find the value of y when x=3 y=2x3 y=0

1 answer:

MaRussiya [10]3 years ago

8 0

Answer: 54

Why? You need to put 3 in for x so you get
2(3)^3
3 to the third power is 3*3*3 which equals 27
2(27)
Now you must do 2 times 27 and you get 54

Hope this helps

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WILL AWARD BRAINLIEST AND 30 PTS IF THERE IS A GOOD EXPLANATION. ANSWER IS NOT 243. question: In how many ways can we put five i

Bumek [7]

Answer:

243 ways

Step-by-step explanation:

Fruits = 5

Bowls = 3

Remember that, There are three bowls for five fruits. So the possible outcomes are:

=> $3^5 = 3*3*3*3*3 = 243$ ways

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3 years ago

Joe borrowed $5,000 from the bank at a rate of 7% simple interest per year. How much interest did he pay in 7 years?

yaroslaw [1]

Answer:

$2450

Step-by-step explanation:

7% of 5000 is 350 which means that she would be paying $350 a year and so if you multiply the amount she pays a year ($350) you would get $2450.

I hope this helps.

5 0

3 years ago

Read 2 more answers

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

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3 years ago

Which is a factor of x2 + 5x – 24?<br> O<br> (x-6)<br> (x + 6)<br> (X-8)<br> (X + 8)

ANTONII [103]

Your answer will be (x+8)

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3 years ago

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If 40% is eliminated from 500 what is left over?

DIA [1.3K]

Answer:

300

Step-by-step explanation:

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3 years ago