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konstantin123 [22]
3 years ago
8

Terry placed 6 numbers tiles labeled 4,7,10,11,14,21 in a box he will pick one of the number tiles from the box without looking

. What is the probability terry will pick a tile labeled with an even number ?
Mathematics
1 answer:
melisa1 [442]3 years ago
7 0
Out of the 6 numbers, 3 of them are even: 4, 10, and 14. The probability that he will pick an even number is therefore 3/6 = 1/2 = .5
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How to make a mixed or whole number 7/3
eimsori [14]

Answer:

mixed number: 7/3= 2 1/3

4 0
3 years ago
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Please help. What would be the proper proof for this problem? Prove: line BE congruent line BD.
Bumek [7]

Answer:

line AB is congruent to line CB . proof: given

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Step-by-step explanation:

Sorry if I'm wrong on this, but I hope you understand the general idea!

5 0
3 years ago
Write an equation. Let x be the unknown number<br> sixteen is 18 less than twice a number.
svlad2 [7]

Answer:

17

Step-by-step explanation:

Let the number be x

16 = 2x - 18

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16+18 = 2x

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7 0
3 years ago
Anna found that there are 34 options for pizzas with different toppings at her local pizzeria. How many total options are there
wel
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4 0
3 years ago
An urn contains 12 balls, of which 4 are white.
wel

Answer:

a) \frac{1}{3}

b) \frac{4}{12}\,,\,\frac{4}{11}\,,\,\frac{4}{10}\,,...

Step-by-step explanation:

Number of balls in the urn = 12

Number of white balls in the urn = 4

So, number of balls which are not white = 12 - 4 = 8

We know that probability = No. of outcomes/Total number of outcomes

Let A_i\,,\,B_i\,,\,C_i denotes the event of getting white ball by A, B and C

a) each ball is replaced after being drawn.

Probability = Number of white balls/Total number of balls

Solution: P(A_i)=P(B_i)=P(C_i)=\frac{4}{12}=\frac{1}{3}

b)the balls that are withdrawn are not replaced.

Solution:

If A wins: P(A_1)=\frac{4}{12}=\frac{1}{3}

If A lost and B wins: P\left ( B_1|A_1^{c} \right )=\frac{4}{11}

If A and B lost and C wins: P\left ( C_1|A_1^{c}\,B_1^{c} \right )=\frac{4}{10}

and so on....

4 0
4 years ago
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