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2 years ago

I really need help! will give brainliest!!

Mathematics

1 answer:

TiliK225 [7]2 years ago

8 0

Answer is A) AC= 20 and angle A=37°
Dilated by factor of 4 means enlarged by 4 ( multiply by 4)

The angle stays the same no matter how much you increase or decrease the size

And AC= 5 x4= 20

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I got the first two can you help me with the last one PLZ

Nat2105 [25]

1. Geometric Sequence

2. $a_n = a_{n-1} * 3$

3. $a_n = 6 * (3)^{n-1}$

Step-by-step explanation:

Given sequence is:

6, 18, 54, 162,....

Here

$a_1 =6\\a_2 = 18\\a_3 = 54$

(a) Is this an arithmetic or geometric sequence?

We can see that the difference between the terms is not same so it cannot be an arithmetic sequence.

We have to check for common ratio (ratio between consecutive terms of a sequence) denoted by r

$r = \frac{a_2}{a_1} = \frac{18}{6}= 3\\r = \frac{a_3}{a_2} = \frac{54}{18} = 3$

As the common ratio is same, the given sequence is a geometric sequence.

(b) How can you find the next number in the sequence?

Recursive formulas are used to find the next number in sequence using previous term

Recursive formula for a geometric sequence is given by:

$a_n = a_{n-1} * r$

In case of given sequence,

$a_n = a_{n-1} * 3$

So to find the 5th term

$a_5 = a_4*3\\a_5 = 162*3\\a_5 = 486$

(c) Give the rule you would use to find the 20th week.

In order to find the pushups for 20th week, explicit formul for sequence will be used.

The general form of explicit formula is given by:

$a_n = a_1 * r^{n-1}$

Putting the values of a_1 and r

$a_n = 6 * (3)^{n-1}$

Hence,

1. Geometric Sequence

2. $a_n = a_{n-1} * 3$

3. $a_n = 6 * (3)^{n-1}$

Keywords: Geometric sequence, common ratio

Learn more about geometric sequence at:

#LearnwithBrainly

4 0

2 years ago

Select the equation written in point-slope form.

slavikrds [6]

Poin slope form is
y-y1=m(x-1)
the answer is A

4 0

2 years ago

Is anyone able to help me?

bogdanovich [222]

Answer:

The volume of this triangular prism is 20 $cm^{3}$

Step-by-step explanation:

Just like it is shown in the picture we can use the formula for the volume of a triangular prism.

$V = \frac{1}{2}bhl$

In our case b = 5cm, h = 2 cm, l = 4cm. Now we just plug in the values and get...

$V = \frac{1}{2}bhl\\\\$

$V = \frac{1}{2}(5)(2)(4)$

$V = 20cm^{3}$

Therefore the volume of the triangular prism is 20 $cm^{3}$ .

7 0

2 years ago

Does anyone know this?

Stels [109]

Every hexagon clearly has 6 sides. Nevertheless, every time you "glue" two hexagons together, you "lose" 2 sides to your count, because the sides where the two hexagons meet are not exterior sides anymore, and so they are not taken into account in our counting.

Also observe that with n hexagons you have n-1 points of contact between hexagons.

Since every hexagon has 6 sides and every gluing point takes away 2 sides, the number of exterior sides with n hexagons is

$s(n)=6n - 2(n-1) = 6n-2n+2=4n+2$

Let's plug some values for n:

$s(1) = 4\cdot 1 + 2 = 4+2 = 6$
$s(2) = 4\cdot 2 + 2 = 8+2 = 10$
$s(3) = 4\cdot 3 + 2 = 12+2 = 14$
$s(4) = 4\cdot 4 + 2 = 16+2 = 18$

You can check that these values are correct by counting the sides on the figure you have.

Finally, we can count the sides of a train with 10 hexagons by plugging n=10 in our formula:

$s(10) = 4\cdot 10 + 2 = 40 + 2 = 42$

Note: the numbers we've given are the number of sides that form the perimeter. So, the actual perimeters are the number of sides multiplied by the length of the side itself: if we let $s$ be the length of the side, the perimeters will be $6s,\ 10s,\ 14s,\ 18s$ for the first 4 trains, and $42s$ for the 10-hexagon train.

6 0

2 years ago

What is 3 root of − 1331 end root ?

NNADVOKAT [17]

∛-1331
∛-11 · (-11) · (-11)
∛-11∛-11∛-11
-11

7 0

2 years ago