Answer:
The answer is C.
Step-by-step explanation:
No because the graph fails the vertical line test.
Step-by-step explanation:
![{ \huge{ \red{ \bf( \frac{3}{4} ) {}^{3} }}}](https://tex.z-dn.net/?f=%7B%20%5Chuge%7B%20%5Cred%7B%20%5Cbf%28%20%5Cfrac%7B3%7D%7B4%7D%20%29%20%7B%7D%5E%7B3%7D%20%7D%7D%7D)
![{ \huge{ \blue{ \bf{( \frac{3 \times 3 \times 3}{4 \times 4 \times 4} )}}}}](https://tex.z-dn.net/?f=%7B%20%5Chuge%7B%20%5Cblue%7B%20%5Cbf%7B%28%20%5Cfrac%7B3%20%5Ctimes%203%20%5Ctimes%203%7D%7B4%20%5Ctimes%204%20%5Ctimes%204%7D%20%29%7D%7D%7D%7D)
![{ \large{ \pink{ \boxed{ \tt{ \bigg( \frac{27}{64} { \bigg)}}}ans.}}}](https://tex.z-dn.net/?f=%7B%20%5Clarge%7B%20%5Cpink%7B%20%5Cboxed%7B%20%5Ctt%7B%20%5Cbigg%28%20%5Cfrac%7B27%7D%7B64%7D%20%7B%20%5Cbigg%29%7D%7D%7Dans.%7D%7D%7D)
Answer: First option.
Step-by-step explanation:
To solve for "h" from the given the equation
, you need to:
Apply the Subtraction property of equality and subtract
to both sides of the equation.
Then you need to apply the Division property of equality and divide both sides of the equation by
.
Then:
![S-2\pi r^2=2\pi rh+2\pi r^2-2\pi r^2\\\\S-2\pi r^2=2\pi rh\\\\\frac{S}{2\pi r}-\frac{2\pi r^2}{2\pi r}=\frac{2\pi rh}{2\pi r}\\\\\frac{S}{2\pi r}-r=h](https://tex.z-dn.net/?f=S-2%5Cpi%20r%5E2%3D2%5Cpi%20rh%2B2%5Cpi%20r%5E2-2%5Cpi%20r%5E2%5C%5C%5C%5CS-2%5Cpi%20r%5E2%3D2%5Cpi%20rh%5C%5C%5C%5C%5Cfrac%7BS%7D%7B2%5Cpi%20r%7D-%5Cfrac%7B2%5Cpi%20r%5E2%7D%7B2%5Cpi%20r%7D%3D%5Cfrac%7B2%5Cpi%20rh%7D%7B2%5Cpi%20r%7D%5C%5C%5C%5C%5Cfrac%7BS%7D%7B2%5Cpi%20r%7D-r%3Dh)
Answer: -5
Step-by-step explanation: 2 + -11 = -9 and subtract -4 from it since it’s the sum of 2 + -6. -9 - -4 is -9 + 4 so -5