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3 years ago

6

On Monday, Rachel bought 13 yards of fabric in order to make face masks. Later that day, she purchased another 6 3/4 yards. On W

ednesday she made a few face masks and used 5 1/10 yards of fabric. How much fabric does Rachel have left?

1 answer:

Vladimir [108]3 years ago

5 0

Answer:

14.65

Step-by-step explanation:

You add 13 + 6 3/4 then subtract 5 1/10 from that and you have your answer.

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Find an equation for the nth term of the arithmetic sequence. a18 = 97, a20 = 281

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What is the midpoint of (3,8) and (6,4)

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Fiona’s school has three hallways that make up three sides of a triangular building design. In the morning, Fiona walks 90 yards

lilavasa [31]

Answer:

"between 30 yards and 150 yards"

Step-by-step explanation:

Let one side of a triangle be x and another side be y. To find the possible lengths of the third side, it is given by:

<u><em>Possible length of 3rd side would be between "x - y" and "x + y"</em></u>

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Here, given x = 90 and y = 60, so the possible length of 3rd side would be:

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2 years ago

Read 2 more answers

Recent census data indicated that 14.2% of adults between the ages of 25 and 34 live with their parents. A random sample of 125

kicyunya [14]

Answer:

The probability is $P(14 < X < 20 ) = 0.5354$

Step-by-step explanation:

From the question we are told that

The proportion that live with their parents is $\r p = 0.142$

The sample size is n = 125

Given that there are two possible outcomes and that this outcomes are independent of each other then we can say the Recent census data follows a Binomial distribution

i.e

$X \ \~ \ B( \mu , \sigma )$

Now the mean is evaluated as

$\mu = n * \r p$

$\mu = 125 * 0.142$

$\mu = 17.75$

Generally the proportion that are not staying with parents is

$\r q = 1 - \r p$

= > $\r q = 0.858$

The standard deviation is mathematically evaluated as

$\sigma = \sqrt{n * \r p * \r q }$

$\sigma = \sqrt{ 125 * 0.142 * 0.858 }$

$\sigma = 3.90$

Given the n is large then we can use normal approximation to evaluate the probability as follows

$P(14 < X < 20 ) = P( \frac{ 14 - 17.75}{3.90}$

Now applying continuity correction

$P(14 < X < 20 ) = P( \frac{ 13.5 - 17.75}{3.90} < \frac{ X - \mu }{\sigma } < \frac{ 19.5 - 17.75}{3.90} )$

Generally

$\frac{ X - \mu }{\sigma } = Z ( The \ standardized \ value \ of X )$

$P(14 < X < 20 ) = P( \frac{ 13.5 - 17.75}{3.90} < Z< \frac{ 19.5 - 17.75}{3.90} )$

$P(14 < X < 20 ) = P( -1.0897 < Z< 0.449 } )$

$P(14 < X < 20 ) = P( Z< 0.449 ) - P(Z < -1.0897)$

So for the z - table

$P( Z< 0.449 ) = 0.67328$

$P(Z < -1.0897) = 0.13792$

$P(14 < X < 20 ) = 0.67328 - 0.13792$

$P(14 < X < 20 ) = 0.5354$

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3 years ago

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Answer:

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Step-by-step explanation:

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