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Elan Coil [88]
3 years ago
6

Activity 1 of 2

Mathematics
2 answers:
Over [174]3 years ago
5 0
Is there a picture to the question
Ray Of Light [21]3 years ago
4 0
The answer is C 180 bc I took the test
You might be interested in
Thank u to da person who is willing to help me will get this Brainliest! :3
kumpel [21]
1) use distributive property
3x - 6 + 5x + 4
8x - 2

2) 4-2x - 14 - 3
-14 - 2x
7 0
3 years ago
Read 2 more answers
PLEASE HELP
Zielflug [23.3K]

Answer:

  • x = 4
  • WX = WY = 25
  • XY = 17

Step-by-step explanation:

The triangle is isosceles with side WX equal to side WY:

  WX = WY

  9x -11 = 7x -3

  2x = 8 . . . . . add 11-7x

  x = 4

Then the side measures are ...

  WX = WY = 7(4) -3 = 28 -3 = 25

  XY = 4(4) +1 = 16 +1 = 17

5 0
2 years ago
Solve the equation using addition or subtraction<br> 22 + 15 = d - 17
agasfer [191]

Answer:

d=54

Step-by-step explanation:

22 + 15 = d - 17

37=d-17

54=d

d=54

3 0
3 years ago
Read 2 more answers
△ABC∼△DEF , △ABC has a height of 14 centimeters, and △DEF has a height of 6 centimeters. What is the ratio of the area of △ABC t
Kamila [148]
Since triangle ABC is similar to triangle DEF then the ratio of the corresponding sides is constant.
The ratio of the corresponding lengths is referred to as the linear scale factor.
Considering the heights of the two triangles;
L.S.F = 14/6
          = 7/3
The ratio in area (A.S.F) is given by (L.S.F)²
Therefore, A.S.F = (7/3)² = 49/9
Thus te ratio of the area of triangle ABC to DEF is 49:9
8 0
3 years ago
Read 2 more answers
After traveling exactly half of its journey from station A to station B, a train was held up for 10 minutes. In order to arrive
Alex17521 [72]
Let's define variables:
 s = original speed
 s + 12 = faster speed
 The time for the half of the route is:
 60 / s
 The time for the second half of the route is:
 60 / (s + 12)
 The equation for the time of the trip is:
 60 / s + 60 / (s + 12) + 1/6 = 120 / s
 Where,
 1/6: held up for 10 minutes (in hours).
 Rewriting the equation we have:
 6s (60) + s (s + 12) = 60 * 6 (s + 12)
 360s + s ^ 2 + 12s = 360s + 4320
 s ^ 2 + 12s = 4320
 s ^ 2 + 12s - 4320 = 0
 We factor the equation:
 (s + 72) (s-60) = 0
 We take the positive root so that the problem makes physical sense.
 s = 60 Km / h
 Answer:
 
The original speed of the train before it was held up is:
 
s = 60 Km / h
8 0
3 years ago
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