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3 years ago

DUE TODAY!!! PLEASE HELP I DIDNT PAY ATTENTION IN CLASS!!! I WILL GIVE BRAINLIEST!!!

Mathematics

1 answer:

leva [86]3 years ago

7 0

The would be segment PR. It yes you the diameter which is needed in finding the circumference.

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What is the distance between 8 and −4

Zinaida [17]

Answer:

The distance is given by |8-(-4)|=|8+4|=|12|=12.

Step-by-step explanation:

pls Mark my answer in brainlist and follow me

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2 years ago

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Does -2 4/5 + 6 1/3= 2/5

aleksandr82 [10.1K]

Answer:

yes.

Step-by-step explanation:

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3 years ago

The arc length l formed by f(x) between x = a and x = b is given by the formula below. find the arc length.

Mamont248 [21]

I got 12345678 m in my bank account

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4 years ago

A distribution of scores for a test of life stressors has a mean of µ = 125 and standard deviation of σ = 15. The researcher cal

laila [671]

Answer:

The mean and standard deviation for the z-scores in this distribution are 0 and 1 respectively.

Step-by-step explanation:

Let the random variable X follow a Normal distribution with mean μ and standard deviation σ.

The z-scores are standardized form of the raw scores X. It is computed by subtracting the mean (μ) from the raw score x and dividing the result by the standard deviation (σ).

$z=\frac{x-\mu}{\sigma}$

These z-scores also follow a normal distribution.

The mean is:

$E(z)=E[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma}\times [E(x)-\mu] =\frac{1}{\sigma}\times [\mu-\mu]=0$

The standard deviation is:

$Var(z)=Var[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma^{2}}\times [Var(x)-Var(\mu)] =\frac{\sigma^{2}-0}{\sigma^{2}}=1\\SD(z)=\sqrt{Var(z)}=1$

Thus, the mean and standard deviation for the z-scores in this distribution are 0 and 1 respectively.

8 0

3 years ago

Perform the indicated operation. Be sure the answer is reduced.

ANTONII [103]

$\frac{m}{n} . \frac{n}{p} \div \frac{p}{q} \\ = \frac{m}{p} \div \frac{p}{q} \\ = \frac{m}{p} . \frac{q}{p} \\ = \frac{mq}{ {p}^{2} }$

Hope it helps...

Regards;

Leukonov/Olegion.

8 0

3 years ago

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