Answer:
ha
Step-by-step explanation:
Answer:
Range is {y | y ≥ –11}
Step-by-step explanation:
This is quadratic equation.
<em>A quadratic equation's range can be found if we find the vertex.</em>
For quadratic equations that have a positive number in front of 
, it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>
The formula for vertex of a parabola is:
Vertex = 
Where,
is the coefficient of 
is the coefficient of 
From our equation given, 
and 
Now, coordinate of vertex is 
coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the value [ 
] into the equation. So we have:
Hence, the range would be all numbers greater than or equal to 
Third answer choice is the right one.
Answer:
x=(3a+5)/(2a-b)
Step-by-step explanation:
We spread the a to the 2x and -3 first,
2ax -3a= bx+5 5ax
By adding 3a, we pass the -3a over
2ax=bx+5+3aa bx+5+3aa
We'll pass the bx over the bx, then
2ax-bx=5+3aa-bx=5
Now we will party like this on the left side,
5+3a) x(2a-b)=5+3a)
Everything we have to do to find x is to separate both sides by (2a-b)
x=(3a+5)/=(3a+5)/ (2a-b)
Answer:
the first one is the answer
