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Ghella [55]
3 years ago
5

What is this answer

Mathematics
1 answer:
mylen [45]3 years ago
7 0

Answer:

t = ≥ 0.1

Step-by-step explanation:

Hope that helps!

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A graph titled Marginal Cost of Bikes has the bike number of the x-axis, from 1 to 7, and marginal cost on the y-axis, from 0 to
aleksklad [387]

Answer:

80

20

50

60

Step-by-step explanation:

subtract the total cost form the bike above the bike in question and thats ur answer

4 0
3 years ago
(1/4)^3+(3/4)^3+3(1/4)(3/4)(1/4+3/4)
bogdanovich [222]
The answer should be 1
6 0
3 years ago
Evaluating expressions:<br> 1. x + 9 when x = 3
balu736 [363]

⇨ The numeric value of this expression = 12.

<h3> </h3>
  • To solve this expression, just <u>replace '</u><u>x</u><u>'</u> by the <em>indicated value</em>, being the number 3, and <em>perform</em> the <em>indicated </em>math <em>operations</em>.

{\large \displaystyle \sf {1 \cdot x+9  }}

{\large \displaystyle \sf {x=3  }}

{\large \displaystyle \sf {1 \cdot 3+9  }}

{\large \displaystyle \sf { 3+9  }}

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \ 12 \   }}}}}}\\\\

  • Therefore, we can conclude that, the correct value of this expression = 12.

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \ 12 \   }}}}}}\\\\

<h3><em>Hope this helps! ❤️</em></h3>

4 0
2 years ago
Using the table what is the value for the range when the domain is 2
Snezhnost [94]

Answer: A) -1

Step-by-step explanation:

4 0
3 years ago
Suppose that the given line has a slope of -2/3 and a y-intercept of (0,5/3). which of the following points is also a solution t
otez555 [7]

Answer:

From five given points it is find that points (1 , 1) and (4 , -1) will apply

Step-by-step explanation:

According to question,

Slop of line (m) = \frac{-2}{3}

And y-intercept is ( 0, \frac{5}{3})

So from above slope and points, the equation of line can be written as

y = mx + c

i.e \frac{5}{3} = \frac{-2}{3} x + c

    \frac{5}{3} = \frac{-2}{3} (0) + c

    \frac{5}{3} = 0 + c

Or, c = \frac{5}{3}

A) With points ( 5, \frac{5}{3} )

   At x = 5, y =\frac{-2}{3} (5) + \frac{5}{3}

            or, y = \frac{-10}{3} + \frac{5}{3}

            so, y = \frac{-5}{3}

Hence this points do not apply

B) With points ( 1 , 1 )

   At x = 1, y =  \frac{-2}{3} (1) +  \frac{5}{3}

      or,      y =  \frac{-2+5}{3}

      So,     y =  \frac{3}{3}

                y = 1

Hence this points will apply

C) With points ( 4 , -1 )

    At x = 4 , y =  \frac{-2}{3} (4) +  \frac{5}{3}

                    y =  \frac{-8+5}{3}

                    y =  \frac{-3}{3}

             So,  y= -1

Hence this points will apply

D) With points (-3 ,7)

    At x = - 3, y = \frac{-2}{3} (-3) +  \frac{5}{3}

                     y = \frac{14}{3}

 Hence this point will not apply

E) with points (0 , 0)

    At x 0,     y =  \frac{-2}{3} (0) +  \frac{5}{3}

               Or, y = 0 +  \frac{5}{3}

                     y =  \frac{5}{3}

Hence this point will not apply

∴ From above five given points it is find that points (1 , 1) and (4 , -1) apply

Answer

7 0
3 years ago
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