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Evgen [1.6K]
4 years ago
5

Find the percent as a fraction. Simplify if possible.33 1/3%

Mathematics
2 answers:
hoa [83]4 years ago
7 0

Answer: 33 1/3% as a fraction is 1/3. It cannot be simplified. Hope this helps!

attashe74 [19]4 years ago
3 0

Answer:

The answer would be 100/3

Step-by-step explanation:

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22?

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3 years ago
The electric cooperative needs to know the mean household usage of electricity by its non-commercial customers in kWh per day. A
vekshin1

Answer:

15.7-2.58\frac{2.3}{\sqrt{1731}}=15.6    

15.7+2.58\frac{2.3}{\sqrt{1731}}=15.8    

We are 99% confident that the true mean of electricity comsumption is between (15.6 and 15.8) kWh

Step-by-step explanation:

Information provided

\bar X= 15.7 represent the sample mean for the usage of electricity

\mu population mean (variable of interest)

\sigma= 2.3 represent the population standard deviation

n=1731 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula if we know the population deviation:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level provided is  0.99 or 95%, the value of significance is \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

And replacing we got:

15.7-2.58\frac{2.3}{\sqrt{1731}}=15.6    

15.7+2.58\frac{2.3}{\sqrt{1731}}=15.8    

We are 99% confident that the true mean of electricity comsumption is between (15.6 and 15.8) kWh

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4 years ago
9 * 10 to the fourth power - 7 * 10 to the second power ​
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89300

Step-by-step explanation:

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