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2 years ago

B) The elephant

Mathematics

2 answers:

olya-2409 [2.1K]2 years ago

5 0

I don’t get it_________

Misha Larkins [42]2 years ago

3 0

Answer:

what!?!!!?!.!?!!!?!!.

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(6) Find a and b as well as the ratio c:d in the<br> figure below.

polet [3.4K]

Answer:

i have a Similar question I’m stuck on, just remember z rule, vertically opposite etc.

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3 years ago

17. Which of the following measures can be calculated for qualitative data? a. Mean b. Median c. Mode d. All of these

VLD [36.1K]

Answer: C. Mode

Step-by-step explanation:

Qualitative data applies to observable data such as reoccurring patterns (mode)

Quantitative data applies to numbers and numerical calculations (Mean, Median)

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3 years ago

Which of the following best describes the type of probability used in the

irga5000 [103]

Awnser is C. Random cuz thats how i chose this answer... its was random

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3 years ago

Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°

natima [27]

$\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0$

$\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}$

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3 years ago

A company makes traffic signs one of those signs can be modeled by an equilateral triangle with the perimeter of 144 inches the

barxatty [35]

Answer:

The height of the larger traffic signs is 51.96 inches

Step-by-step explanation:

Given that initially, A company makes traffic signs of an equilateral triangle with the perimeter of 144 inches

Now, A company makes similar traffic signs of perimeter 1.25 of original

New perimeter will be 1.25x144=180 inches

Let triangle ABC be a larger triangle with 180inches of the perimeter.

It is given that the triangle is an equilateral triangle,

Therefore, Side AB=BC=AC

The perimeter of a triangle ABC is

AB+BC+AC=180

3AB=180

AB=60 inches

Figure show that triangle ABC and AD is the height of the triangle.

Since, the triangle ABC is an equilateral triangle,

AD is the perpendicular bisector of BC

so that,

BD=DC and Angle ADB=90

In right triangle ADB,

Angle D =90 and Angle B =60

Side BD=60/2=30 inches and AB=60 inches

Using Pythagoras theorem,

$AD^{2} +BD^{2} =AC^{2}$

$(AD)^{2} +(30)^{2} =60^{2}$

$(AD)^{2} =60^{2}-(30)^{2}$

AD=51.96 inches

Thus, The height of the larger traffic signs is 51.96 inches

4 0

3 years ago