Question

A system of linear equations includes the line that is created by the equation y = x+ 3, graphed below, and the line through the points (3, 1) and (4, 3).
On a coordinate plane, a line goes through (0, 3) and (2, 5).

What is the solution to the system of equations?

(–1, 2)

(1, 3)

(8, 11)

(9, 12)

i really dont get this at all can someone help me and explain

Answer 1

Answer:

(8,11)

Step-by-step explanation:

1st line

y = x+ 3

We need to find the equation of the other line

We have two points (3, 1) and (4, 3)

Slope

m = (y2-y1)/(x2-x1)

   = ( 3-1)/(4-3)

   = 2/1 = 2

The slope intercept form is y = mx+b where m is the slope and b is the y intercept

y =2x+b

Using the point (4,3)

3 = 2(4)+b

3 = 8+b

3-8=b

-5 =b

y = 2x-5

We have 2 lines

y =x+3 and y = 2x-5

Setting them equal to each other

x+3 = 2x-5

Subtract x from each side

x+3-x = 2x-5-x

3 = x-5

Add 5 to each side

3+5 =x-5+5

8=x

Now we can find y

y =x+3

y = 8+3

y=11