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Snezhnost [94]
3 years ago
9

How do I do this its systems of equations

Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0
Let x the subject of the equation in x-2y=-10 this make it x=2y-10 substitute this in the first equation. 3(2y-10)-2y=-6 solve for y, y=6. substitute y in any of the original equations to get x x= 2
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How many quarts of soil are used to fill 2 flower pots?<br> Each pot holds 3 2/5
nikklg [1K]

Answer:

6.8

Step-by-step explanation:

If each pot holds 3 2/5 quarts each and there are two then you add them together to see how much is needed

8 0
2 years ago
One package of tile will cover 3 square feet.How many packages will shee need 8,13,15,39
IrinaVladis [17]

Hey there! :)

Answer:

13 packages.

Step-by-step explanation:

Begin by finding the total area of this composite figure. Separate the figure into separate rectangles. Use the formula A = l × w to calculate the area of each:

Smaller rectangle:

Subtract 7 from 9 to find the width:

9 -7 = 2. Therefore:

2 × 2 = 4 ft².

Larger rectangle:

7 × 5 = 35 ft².

Add up the two areas to find the area of the entire figure:

4 + 35 = 39 ft².

If each package of tile covers 3 ft², simply divide to find the package of tiles needed:

39 / 3 = 13 packages.

4 0
3 years ago
Height = 5cm<br> Base = 12cm
stepladder [879]
The answer would be 60 because you do based times height which equals the area
4 0
3 years ago
Read 2 more answers
Helpp plz I will mark brainliestttt
Julli [10]

Answer:

Answer b

Step-by-step explanation:

Mark brainliest

5 0
3 years ago
Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimet
Mumz [18]

Answer:

296.693\leq x\leq 319.307

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }

Where x' is the sample mean, s is the population standard deviation, n is the sample size and z_{\alpha /2} is the z-score that let a proportion of \alpha /2 on the right tail.

\alpha is calculated as: 100%-99%=1%

So, z_{\alpha/2}=z_{0.005}=2.576

Finally, replacing the values of x' by 308, s by 17, n by 15 and z_{\alpha /2} by 2.576, we get that the confidence interval is:

308-2.576\frac{17}{\sqrt{15} } \leq x\leq 308+2.576\frac{17}{\sqrt{15} }\\308-11.307 \leq x\leq 308+11.307\\296.693\leq x\leq 319.307

6 0
3 years ago
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