The angle between two vectors is given by:
cos (x) = (v1.v2) / (lv1l * lv2l)
We have then:
v1.v2 = (2, -5). (4, -3)
v1.v2 = (2 * 4) + (-5 * (- 3))
v1.v2 = 8 + 15
v1.v2 = 23
We look for the vector module:
lv1l = root ((2) ^ 2 + (-5) ^ 2)
lv1l = 5.385164807
lv2l = root ((4) ^ 2 + (-3) ^ 2)
lv2l = 5
Substituting values:
cos (x) = (23) / ((5.385164807) * (5))
x = acos ((23) / ((5.385164807) * (5)))
x = 31.33 degrees
Answer:
The angle between the two vectors is:
x = 31.33 degrees
2y+20=100
2y=80
y=40
The explanation for this would because because the two base angles of an isosceles triangle are equal so since the both equal to 40 degrees, in total would be 80 degrees.
Since the total degrees of a triangle is 180 and you know the base angles make up for 80 percent you subtract that from the total of the angle your trying to find, which is 2y+20.
Answer:
Step-by-step explanation:
Yes
Theorem 8.3: If two angles are complementary to the same angle, then these two angles are congruent.
∠A and ∠B are complementary, and ∠C and ∠B are complementary.
Given: ∠A and ∠B are complementary, and ∠C and ∠B are complementary.
Prove: ∠A ~= ∠C.
Statements Reasons
1. ∠A and ∠B are complementary, and ∠C and ∠B are complementary. Given
2. m∠A + m∠B = 90º , m∠C + m∠B = 90º Definition of complementary
3. m∠A = 90 º - m∠B, m∠C = 90º - m∠B Subtraction property of equality
4. m∠A = m∠C Substitution (step 3)
5. ∠A ~= ∠C Definition of ~=
The length of both AB and DC is the same.
19 degrees
We want to know the arc measure for the whole circle, except for DC. So, we can subtract the arc measure of DC from 360 to find DBC. Since we found DC above, all we need to do is subtract.
360 - 19 = 341
DBC = 341 degrees
Hope this helps!! :)
2.3 i think let me know if it works
