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3 years ago

Explain how to do (2^-2/3^3)^4 i need to know how to do this.

Mathematics

1 answer:

cricket20 [7]3 years ago

5 0

Answer:

((2^(-2))÷(3^3))^4=

Step-by-step explanation: expand

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10) A population decreases from 14,500 to 12,035. What is the percent change?

Gnesinka [82]

Answer:

83%

Step-by-step explanation:

14500 .......... 100%

12035 ................x%

x = 12035*100/14500 = 12035/145 = 83%

8 0

3 years ago

The number of measles cases increased 13.6 % to 57 cases this year, what was the number of cases prior to the increase? (Express

ELEN [110]

Answer:

The number of cases prior to the increase is 50.

Step-by-step explanation:

It is given that the number of measles cases increased by 13.6% and the number of cases after increase is 57.

We need to find the number of cases prior to the increase.

Let x be the number of cases prior to the increase.

x + 13.6% of x = 57

$x+x\times \frac{13.6}{100}=57$

$x+0.136x=57$

$1.136x=57$

Divide both the sides by 1.136.

$\frac{1.136x}{1.136}=\frac{57}{1.136}$

$x=50.176$

$x\approx 50$

Therefore the number of cases prior to the increase is 50.

7 0

3 years ago

participar de uma maratona um atleta inicia um treinamento mensal, em que corre todo dia e sempre 2 minutos a mais do que correu

AleksandrR [38]

Answer:

59 minutes

Step-by-step explanation:

In the table of values it is observed that for each day of training 2 minutes are increasing and that day 1 begins with 5 minutes of training , so

$y(x)=2\frac{min}{d}(x)+3min$ , where x= evaluation day

we have to for the day 28

$y(28)=2\frac{min}{d}(28d)+3min=59min$

7 0

4 years ago

For each function, find f(-2), f(-0.5), and f(3). 1. f(x)=-x 4 2. f(x)= 3/8x-3

TEA [102]

f(-2)=-2+4, f(-0.5)=-0.5+4, f(3)=-3+4

f(x) = -(-2) +4 f(x) = -(0.5) + 4 f(x) = -(3) +4

6 0

3 years ago

Exams are approaching and Helen is allocating time to studying for exams. She feels that with the appropriate amount of studying

svp [43]

Answer: 0.05

Step-by-step explanation:

Let M = Event of getting an A in Marketing class.

S = Event of getting an A in Spanish class,

i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45

Required probability = P(neither M nor S)

= P(M'∩S')

= P(M∪S)' [∵P(A'∩B')=P(A∪B)']

=1- P(M∪S) [∵P(A')=1-P(A)]

= 1- (P(M)+P(S)- P(M∩S)) [∵P(A∪B)=P(A)+P(B)-P(A∩B)]

= 1- (0.80+0.60-0.45)

= 1- 0.95

= 0.05

hence, the probability that Helen does not get an A in either class= 0.05

3 0

4 years ago