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german
3 years ago
8

Explain how to do (2^-2/3^3)^4 i need to know how to do this.

Mathematics
1 answer:
cricket20 [7]3 years ago
5 0

Answer:

((2^(-2))÷(3^3))^4=

Step-by-step explanation: expand

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Veronica's fall football league has a phone tree in case games or practices are postponed. The coach calls 3 players. Then, each
zepelin [54]

Answer:

39

Step-by-step explanation:

the first three call 3, making it 3*3, then each of them will get 3 more, making it 3+(3*3)+(3*3*3),3+9+27, 39

7 0
4 years ago
Read 2 more answers
What would -32 - 24 become if you rewrote the problem to adding the opposite?
Travka [436]

Answer:

If you add it the opposite then it would have a larger sum

Step-by-step explanation:

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3 years ago
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Scale Factor<br><br> Smaller Figure:<br> Larger Figure:<br> Please please help, no links
slega [8]

Answer:

2/3

Step-by-step explanation:

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6 0
3 years ago
Helpppp confused
Sveta_85 [38]

Not an expertise on infinite sums but the most straightforward explanation is that infinity isn't a number.

Let's see if there are anything we missed:

 ∞

 Σ  2^n=1+2+4+8+16+...

n=0

We multiply (2-1) on both sides:

       ∞

(2-1)  Σ  2^n=(2-1)1+2+4+8+16+...

      n=0

And we expand;

 ∞

 Σ  2^n=(2+4+8+16+32+...)-(1+2+4+8+16+...)

n=0

But now, imagine that the expression 1+2+4+8+16+... have the last term of 2^n, where n is infinity, then the expression of 2+4+8+16+32+... must have the last term of 2(2^n), then if we cancel out the term, we are still missing one more term to write:

 ∞

 Σ  2^n=-1+2(2^n)

n=0

If n is infinity, then 2^n must also be infinity. So technically, this goes back to infinity.

Although we set a finite term for both expressions, the further we list the terms, they will sooner or later approach infinity.

Yep, this shows how weird the infinity sign is.

5 0
3 years ago
Using the following equation, find the center and radius:
rodikova [14]

Answer: 4) The center is located at (1, 3), and the radius is 6

Step-by-step explanation:

Solve the general equation of the circle.

x^2 -2x +1+ y^2-6y+9= 26+1+9 (x-1)^2+(y-3)^2=36=6^2

Hence, the coordinates of the center (1,3) And the radius will be 6

4 0
3 years ago
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