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skad [1K]
3 years ago
5

3.5 m

Mathematics
1 answer:
marysya [2.9K]3 years ago
4 0

Answer:

This question seems to be incomplete, I guess that we have a circular pool, with a diameter of 3.5 m.

Now, the circunference of a circle can be written as:

C = 2*pi*r

where:

pi = 3.14

r = radius = half of the diameter = 3.5m/2 = 1.75m

Then replacing those values in the equation for the circumference we have:

C = 2*3.14*1.75m = 10.99 m.

And knowing that the value of pi is actually larger than 3.14 (pi = 3.1415926535....)

We can safely round up the circumference to the next whole number, C = 11m

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A normal population has a mean of 12.2 and a standard deviation of 2.5. compute the z value associated with 14.3. what proportio
Citrus2011 [14]
The z-score associated with 14.3 is 0.84.  0.2995 of the population is between 12.2 and 14.3.  0.1894 of the population is less than 10.0.

The formula for a z-score is

z=(X-μ)/σ

With our data, we have:
z=(14.3-12.2)/2.5=0.84

The z-score associated with the mean is 0.5.  To find the proportion of the population between the mean and 14.3, subtract 0.7995 (the proportion of population below the z-score of 0.84, using http://www.z-table.com) and 0.5:

0.7995 - 0.5 = 0.2995.

The z-score for 10.0 is

(10.0-12.2)/2.5 = -0.88.  The proportion of the population less than this is 0.1894.
5 0
3 years ago
Which line shows the first error in the solution?
Arlecino [84]
Error
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3 0
3 years ago
(GIVING BRAINLYIST) 5 cakes are shared equally between 6 people. What fraction of a cake does each person receive? use fraction
Keith_Richards [23]

Answer:

5/6

Step-by-step explanation:

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Based on the data given in the picture, calculate the area of the car track...
Verizon [17]

Refer to the diagram below. We need to find the areas of the green and blue regions, then subtract to get the area of the orange track only.

The larger green region is composed of a rectangle of dimensions 200 meters by 4+42+4 = 50 meters, along with two semicircles that combine to make a full circle. This circle has radius 25 meters.

The green rectangle has area 200*50 = 10000 square meters. The green semicircles combine to form an area of pi*r^2 = pi*25^2 = 625pi square meters. In total, the full green area is 10000+625pi square meters. I'm leaving things in terms of pi for now. The approximation will come later.

The blue area is the same story, but smaller dimensions. The blue rectangle has dimensions 200 meters by 42 meters, so its area is 200*42 = 8400 square meters. The blue semicircular pieces combine to a circle with area pi*r^2 = pi*21^2 = 441pi square meters. In total, the blue region has area 8400+441pi square meters.

After we figure out the green and blue areas, we subtract to get the orange region's area, which is the area of the track only.

orange area = (green) - (blue)

track area = (10000+625pi) - (8400+441pi)

track area = 10000+625pi - 8400-441pi

track area = (10000-8400) + (625pi - 441pi)

track area = 184pi + 1600 is the exact area in terms of pi

track area = 2178.05304826052 is the approximate area when you use the pi constant built into your calculator. If you use pi = 3.14 instead, then you'll get 2177.76 as the approximate answer. I think its better to use the more accurate version of pi. Of course, be sure to listen/follow your teachers instructions.

4 0
3 years ago
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