Answer:
<h2><em>
46.4°</em></h2>
Step-by-step explanation:
Find the diagrammatic representation in the attachment given.
We can see that the diagram is a right angled triangle. To get the angle of elevation, we will use one of the trigonometry identity SOH, CAH, TOA.
Given the adjacent of the triangle to be 2miles (observation spot from the point of launch)and the opposite (side facing the elevation angle) as 2.1miles (the height), we will use TOA.
tan∅ = opposite/adjacent
tan∅ = 2.1/2
tan∅ = 1.05
∅ = tan⁻¹1.05
∅ = 46.4°
<em>Hence the angle of elevation from Kim to the space shuttle, which is at a height of 2.1 miles is approximately 46.4°</em>
Answer:
C
Step-by-step explanation:
Answer:
for (8,4) is 2 and for (20,_4) is _5
Answer: 5 Seconds
Step-by-step explanation: Given the equation of the height expressed ad;
h(t) = - 16t^2 + initial height
Given that initial height = 400feet
h(t) = - 16t^2 + 400
The waste will hit the ground at when h(t) = 0
substitute
0 = - 16t^2 + 400
16t^2 = 400
t² = 400/16
t² = 25
t = √25
t = 5secs
Area of rectangle = 15 x 8
=120
area of parallelogram = 8 x 15
=120
so, they have the same area, because the length of a rectangle is the same as the height of a parallelogram and also for the base.