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Tatiana [17]
3 years ago
6

PICK ME!!! Abel uses a probability simulator to roll a six-sided number cube 100 times and to flip a coin 100 times. The results

of the experiment are shown below: Number on the Cube Number of Times Rolled 1 12 2 18 3 30 4 22 5 10 6 8 Heads Tails 34 66 Using Abel's simulation, what is the probability of rolling a 2 on the number cube and the coin landing on tails? PICK ME!!! plzz hurry
Mathematics
1 answer:
tatuchka [14]3 years ago
4 0
I think it is 1/3 but I am not sure. Sorry if wrong.
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Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

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