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likoan [24]
3 years ago
7

I need help with 14 and 15

Mathematics
2 answers:
salantis [7]3 years ago
7 0
14= 3 over 4 x I think
15 is 1
In-s [12.5K]3 years ago
5 0

Answer:

I know that 14 B and I am not about 15 but the answer has to be negative. Hope this helps a little.

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A boy at an amusement park has 38 ride tickets. Each ride on the roller coaster costs 5 tickets. After riding the roller coaster
Rina8888 [55]

Answer:

He will expend 35 tickets for 7 rides. 3 tickets are left.

Step-by-step explanation:

Giving the following information:

Number of tickets= 38

Tickets per ride= 5

<u>To calculate the number of rides he can make, we need to use the following formula:</u>

Number of rides= number of tickets / tickets per ride

Number of rides= 38/5

Number of rides= 7.6 = 7 rides

He will expend 35 tickets for 7 rides. 3 tickets are left.

5 0
3 years ago
Pls help! which of the following equations is written in standard form ?
EastWind [94]
Pretty sure the answer is B.
8 0
3 years ago
Solve the system of equations algebraically: x^2 +y^2 =25, y=x^2 +3
aalyn [17]

Answer:

{ \tt{ {x}^{2} +  {y}^{2}  = 25 -  -  -  \{eqn(a) \}}} \\ { \tt{y =  {x}^{2} + 3 -  -  -  \{eqn(b) \} }}

» substitute y in eqn(a) with y in eqn(b)

{ \tt{ {x}^{2} + ( {x}^{2}  + 3) {}^{2}   = 25}}  \\ { \tt{ {x}^{2}  + ( {x}^{2}  + 6x + 9) = 25}} \\ { \tt{2 {x}^{2} + 6x + 9 = 25 }} \\ { \tt{2 {x}^{2}  + 6x - 16 = 0}} \\ { \tt{x = 1.7 \:  \: and \:  \:  - 4.7}}

» Find y in eqn(b)

{ \tt{y =  {x}^{2} + 3 }} \\ { \tt{y = 5.89 \:  \: and \:  \: 25.09}}

8 0
2 years ago
What is 15 1/8 minus 1 3/5?
d1i1m1o1n [39]
I hope this helps you

8 0
3 years ago
Please helps?!?!?!?!?!?!?!?!?!
mestny [16]

Answer:

47x^3\sqrt{5x}

Step-by-step explanation:

The objective is to combine the terms to make one radical, so therefore we know that we will have to take a \sqrt{5} out of the second radical \sqrt{180}.

If we divide 180 by 5, we will get 36, so now we have

\sqrt{180}=\sqrt{5}×\sqrt{36}

\sqrt{36} can be simplied into just 6.

So now the expression becomes

-\sqrt{5x^7}+8x^2*6 \sqrt{5x^3}

Then we can further simplify by moving the x^{2} into the radical to get two common terms with \sqrt{5x^7}.

x^{2} =\sqrt{x^4}, so we now have

-\sqrt{5x^7}+ 8\sqrt{x^4} *6 \sqrt{5x^3}

So then we can combine the two radicals to get the expression to

-\sqrt{5x^7}+48\sqrt{5x^7}

We now see that we have two terms with a common radical, and coefficients of -1, and 48.

That allows us to simplify further to

47\sqrt{5x^7}

Here, we can take out \sqrt{x^6}, which is x^3, and get the final simplied form to be

47x^3\sqrt{5x}

Hope this helped.

7 0
3 years ago
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