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2 years ago

PLEASE HELP I HAVE 5 MINUTES LEFT AND IM HALFWAY DONE PLEASE HELP ASDHA;EFhTHS

Mathematics

1 answer:

galben [10]2 years ago

7 0

Answer:

12 is 52 i think. i am not sure about 11.

Step-by-step explanation:

im so sorry i know 11:(

I hope this helps on 12 tho

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An extremely large sink hole has opened up in a field just outside of the city limits. It is difficult to measure across the sin

abruzzese [7]

Triangle ABC and triangle DCE are congruent, so line DE = line AB

Use the cosine rule to find angle ACB
$52.2^{2}= 50^{2}+ 70^{2}-(2*50*70*cos(ACB))$
$2724.84=7400-(7000cos(ACB))$
$2724.84-7400=-7000cos(ACB)$
$-4675.16=-7000cos(ACB)$
$\frac{4675.16}{7000}=cos(ACB)$
$Angle ACB= cos^{-1} ( \frac{4675.16}{7000})$
Angle ACB = 48.1°

5 0

3 years ago

The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.

VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

$\int\limits^2_{-1} {(f(x) - g(x))} \, dx$

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx$

We know that:

$\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}$

$\int\limits^{}_{} {1} \, dx = x$

$\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}$

Then our integral is:

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2} + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3} + (-1) - \frac{(-1)^2}{2} )$

The right side is equal to:

$(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6$

The bounded area is 5 + 5/6 square units.

3 0

2 years ago

senior citizens receive a 10% discount off the price of a regular dinner special at the dinner bell restaurant. if the cost for

Inessa05 [86]

You can do 1st $12.60 divided by 100 is 0.126 then you do 0.126x10= 1.26 then you add the special price which is $12.60 plus $1.26= $13.86 that is the original price for the dinner.

8 0

3 years ago

Carl played a new video game 20 times and won 13 times. If he continues to win at the same rate, which proportion can Carl use t

Sati [7]

Answer:

Step-by-step explanation:

Do 150 divided by 20 which is 7.5 then do 13 x 7.5 which is 97.5 BUT you cant win 97.5 times do I believe that it would be 97 (if that's not an option, do 98)

8 0

2 years ago

Use the function f(x) = 4x2 − 7x − 15 to answer the questions. Part A: Completely factor f(x). (2 points) Part B: What are the x

makkiz [27]

Answer:

Part A: f(x) = 4·x² - 7·x-15 = (x - 3)·(4·x + 5)

Part B: The x-intercepts are x = 3 and -1.25 #

Part C: As x approaches ∞, y approaches ∞, as x approaches -∞, y approaches ∞

Part D: The graph is a u-shaped quadratic equation graph passing though the x-intercept points -1.25 and 3 on the x-axis and the y-intercept point -15 on the y-axis. Both sides of the symmetrical graph curve extending to infinity

Step-by-step explanation:

The function 4·x² - 7·x-15

To factorize the expression, we have at the 0 factors;

$x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}$

Where;

a = 4, b = -7, c -15, substituting gives;

$x = \dfrac{-(-7)\pm \sqrt{(-7)^{2}-4\times 4\times (-15)}}{2\times 4} = \dfrac{7\pm 17}{8} = 3 \ or -1.25$

Which gives;

(x - 3)·(x + 1.25) = (x - 3)·(4·x + 5)

f(x) = 4·x² - 7·x-15 = (x - 3)·(4·x + 5)

Part B: The x-intercepts are the point where y = 0, which are x = 3 and -1.25 as shown above

Part C: As x approaches ∞, y approaches ∞, as x approaches -∞, y approaches ∞

Part D: With the the nature of the function as y approaches ∞ and -∞ the graph is a u-shaped graph of a quadratic equation passing though the points -1.25 and 3 on the x-axis and the point -15 on the y-axis.

6 0

3 years ago