First: work out the difference (decrease) between the two numbers you are comparing. Then divide the decrease by the original number and multiply the answer by 100. If your answer is a negative number, then this is a percentage increase. :)
X^2+10x+29=0
Quadratic Formula:
−b±√b^2−4(ac)/2a
Substitute the values :
a=1, b=−10, and c=29
into the quadratic formula and solve for
x.
10±√(−10)^2−4•(1•29)/ 2•1
Simplify.
Answer: x=5±2i
Answer:
D
Step-by-step explanation:
BH is perpendicular to AC since an orthocenter is a point at which the three altitudes of a triangle intersect. The altitude of a triangle is that line that passes through its vertex and is perpendicular to the opposite side. Since you know that BH is an altitude due to Point H being an orthocenter, you know that BH is perpedendicular to AC.
D) 256; 1,296 ^ 3/4; ^ 4square root of1,296 ^ 3
Let's rewrite the expression step by step:
1296 ^ 3/4
(1296) ^ (3/4)
(1296 ^ 3) ^ (1/4)
(2176782336) ^ (1/4)
216
This result is different from 256.
Answer:
D) 256; 1,296 ^ 3/4; ^ 4square root of1,296 ^ 3
Answer:

Step-by-step explanation:
Given:
![m\angle PTS = [11(y-10)]\°](https://tex.z-dn.net/?f=m%5Cangle%20PTS%20%3D%20%5B11%28y-10%29%5D%5C%C2%B0)

We need to find the 
Solution:
Now we know that:
By Vertical angles theorem which states that;
"Angles that are opposite each other and formed by two intersecting straight lines, are congruent."


Applying distributive property we get;

Combining like terms we get;

Dividing both side by 7 we get;

Substituting the value of 'y' we get;
![m\angle PTS = [11(y-10)]\°= [11(15-10)]\°= 55\°\\\\m\angle PTS = 55\°](https://tex.z-dn.net/?f=m%5Cangle%20PTS%20%3D%20%5B11%28y-10%29%5D%5C%C2%B0%3D%20%5B11%2815-10%29%5D%5C%C2%B0%3D%2055%5C%C2%B0%5C%5C%5C%5Cm%5Cangle%20PTS%20%3D%20%2055%5C%C2%B0)
Hence The Final Answer is 