I would tell you darling but they don’t make 80 did you add a mistake to the numbers?
Answer:
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If its multi choice then its B
There are 625 different 4-digit codes only made with odd numbers.
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How many different combinations can you make?</h3>
To find the total number of combinations, we need to find the number of options for each one of the digits.
There are 4 digits, such that each digit can only be an odd number.
- For the first digit, there are 5 options {1, 3, 5, 7, 9}
- For the second digit, there are 5 options {1, 3, 5, 7, 9}
- For the third digit, there are 5 options {1, 3, 5, 7, 9}
- For the fourth digit, there are 5 options {1, 3, 5, 7, 9}
The total number of different combinations is given by the product between the numbers of options, so we have:
C = 5*5*5*5 = 625.
There are 625 different 4-digit codes only made with odd numbers.
If you want to learn more about combinations:
brainly.com/question/11732255
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Answer:
n=11
Step-by-step explanation:
(n+4)/10 = (n-8)/2
We can solve using cross products
(n+4) * 2 = 10 * ( n-8)
Distribute
2n+8 = 10n -80
Subtract 2n from each side
2n+8-2n = 10n-80-2n
8 = 8n-80
Add 80 to each side
8+80= 8n-80+80
88 = 8n
Divide each side by 8
88/8 = 8n/8
11 = n