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3 years ago

Help please<333 with an explanation <333 :]]]

Mathematics

1 answer:

lesantik [10]3 years ago

6 0

The first table on the top left is up 3 over 2, the formula is y1-y2/x1-x2 so in this case 3-6/2-4 = -3/-2 = 3/2. Hope this helps!

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In the diagram, ABC = AWRS. What is the perimeter of

vovangra [49]

There is no diagram, so you should guess C. C is the most likely to be chosen as an answer.

3 0

3 years ago

Please help me i only have few hours left i need as much as I can ge. ill get you brainliest and send you free mr.beast merch

masya89 [10]

Answer:

26cm²

Step-by-step explanation:

Perimeter

2x - 4 + 5x - 13 + x + 9 = 40

8x - 8 = 40

8x = 40 - 8

8x = 32

x = 4

Sides of the triangle

Height = 2x - 4 = 2 x 4 - 4 = 4cm

Hypotenuse = 5x - 13 = 5 x 4 - 13 = 7cm

Base = x + 9 = 4 + 9 = 13cm

Area of triangle

= 1/2 x base x height

= 1/2 x 13 x 4

= 26cm²

Hope this helps

7 0

3 years ago

Read 2 more answers

A rectangular storage container with an open top is to have a volume of 10 m3 . then length of its base is twice the width. mate

katrin [286]

Answer:

The cost of materials for the cheapest such container is $163.54.

Step-by-step explanation:

A rectangular storage container with an open top is to have a volume of 10 m³.

The volume of the rectangle is

$\text{Volume} =\text{Length} \times \text{Width} \times \text{Height}$

Length of its base is twice the width.

Let Width be 'w'.

Length is l=2w.

Height be 'h'.

$10 =2w\times w\times h$

$10=2w^2h$

The height in terms of width is represented as,

$h=\frac{10}{2w^2}$

$h=\frac{5}{w^2}$

According to question,

The cost is 10 times the area of the base and 6 times the total area of the sides.

i.e. Cost is given by,

$C=10(L\times W)+6(2\times L\times H+2\times W\times H)$

$C=10(2w\times w)+6(2\times 2w\times \frac{5}{w^2}+2\times w\times \frac{5}{w^2})$

$C=20w^2+\frac{120}{w}+\frac{60}{w}$

$C(w)=20w^2+\frac{180}{w}$

To get the minimum value,

Differentiate the cost w.r.t 'w',

$C'(w)=20\frac{d(w^2)}{dw}+180\frac{d(w^{-1})}{dw}$

$C'(w)=20\times 2w-180 w^{-2}$

$C'(w)=40w-\frac{180}{w^2}$

To find critical points put derivate =0,

$40w-\frac{180}{w^2}=0$

$40w=\frac{180}{w^2}$

$w^3=\frac{180}{40}$

$w=\sqrt[3]{4.5}$

$w=1.65$

We find the second derivative to minimize,

$C''(w)=40\frac{d(w)}{dw}-180\frac{d(w^{-2})}{dw}$

$C''(w)=40+360(w^{-3})$

$C''(w)>0$

As $C''(w)>0$ it is the minimum cost.

The cost is minimum at w=1.65.

Substitute the values in the cost function,

$C(1.65)=20(1.65)^2+\frac{180}{1.65}$

$C(1.65)=54.45+109.09$

$C(1.65)=163.54$

Therefore, the cost of materials for the cheapest such container is $163.54.

7 0

4 years ago

What is the x-intercept on the equation y=2x-10

Mrrafil [7]

The x-intercept is the point where the graph intersects the y-axis.
At the y-axis, all points have 0 for the y-coordinate.
Let y = 0, and solve for x.

y = 2x - 10

0 = 2x - 10

10 = 2x

5 = x

x = 5

The x-intercept is 5.

5 0

4 years ago

Read 2 more answers

Which of the following coordinates exits on the line y=3x+2

raketka [301]

It is B

-2 =3(-1) + 1

3 0

3 years ago