Question

Dylan has a square piece of metal that measures 16 inches on each side. He cuts the metal along the diagonal, forming two right triangles. What is the length of the hypotenuse of each right triangle to the nearest tenth of an inch?
The length of the hypotenuse of each right triangle is how many
inches?

ANSWER PLEASE ASAP♥️

Answer 1

Answer:

Step-by-steThe area of a circle is \pi r^2πr

2

pi, r, squared.

\greenD{\pi \times 2\,\text{cm} \times 2 \,\text{cm}= 4\pi\,\text{cm}^2}π×2cm×2cm=4πcm

2

start color #1fab54, pi, times, 2, start text, c, m, end text, times, 2, start text, c, m, end text, equals, 4, pi, start text, c, m, end text, squared, end color #1fab54

Hint #55 / 6

Finally, subtract the area of the inner circle from the area of the outer rectangle.

Hint #66 / 6

\blueD{132\,\text{cm}^2} - \greenD{4\pi\,\text{cm}^2}\approx 119.43\,\text{cm}^2132cm

2

−4πcm

2

≈119.43cm

2

p explanation: