Answer:
d^2 - π(d/2)^2
Step-by-step explanation:
Since the diameter of the circle is equal to the side of a square (d), that means that we have a circle inscribed in square.
If we draw a square and inscribe a circle in it, all parts of the square outside the circle will be waste, in this particular case.
If we want to find the area of the wasted material we need to subtract the area of the circle from the area of the square.
Area of the circle is:
P1 = πr^2, r being the radius
Since radius is half the diameter, that means that:
P1 = π • (d/2)^2
Area of the square whose side is d is:
P2 = d^2
So, the area of wasted material is:
P = P2 - P1
P = d^2 - π(d/2)^2
Do a sentence, then add a zero at the end of that sentence
Answer:
3.1 Modifying Above 1 with bar is the correct answer .
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Answer: 25 < P < 36
15/4 < w < 26/4
35/4 < L < 46/4
<u>Step-by-step explanation:</u>
Perimeter is BETWEEN 25 and 36
25 < P < 36
Graph: O--------------O
25 36
Perimeter = 2L + 2w ; substitute L = w + 5
25 < 2(w + 5) + 2w < 36
25 < 2w + 10 + 2w < 36
25 < 4w + 10 < 36
15 < 4w < 26
< w < 
< w < 
Graph: O------------------------O

Perimeter = 2L + 2w ; L = w + 5 --> w = L - 5
25 < 2L + 2(L - 5) < 36
25 < 2L + 2L - 10 < 36
25 < 4L - 10 < 36
35 < 4L < 46
< L < 
< L < 
Graph: O------------------------O

Note: Make sure you use OPEN dots when graphing.