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4 years ago

Y'all- this question make's 0 sense to my big brain help me out

Mathematics

1 answer:

gregori [183]4 years ago

3 0

Answer:

D. for the first one, A. for the second (not certain)

Step-by-step explanation:

1. 36/2 (two books every visit) = 18, multiplied by 3 because that's how many often he does to the library (every 3 weeks)

2. 13/2 = w/5 because for every 13 cups of water, there is two cups of cleaner, so for w (unknown amount of water) there would be 5 cups of concontrated cleaner.

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27.54 divided by 5.1

Taya2010 [7]

Answer:

5.4

Step-by-step explanation:

27.54 divided by 5.1 is simply 5.4

6 0

3 years ago

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Mariana and Vicky both solved 617 divided 6. Mariana got 12 remainder 5 as her answer. Vicky got 102 remainder 5 as her answer.

valentina_108 [34]

Answer:

617 ÷ 6

Dividing in order from left to right:

6 into 6 goes once.

6 into 1 doesn't so carry the 1 to the next number

6 into 17 goes twice, remainder 5

So we have: 102 remainder 5.

Vicky is correct.

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3 years ago

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Find all solutions for the absolute value equation |2x - 3| = x + 3.

Fed [463]

$1.\\2x-3=x+3\\\\x=6\\\\2.\\3-2x=x+3\\\\3x=0\\\\x=0\\\\x\in\{0,6\}$

7 0

4 years ago

How can a decimal be converted to percentage?

PtichkaEL [24]

A decimal can be converted to percent by multiplying by 100. Example 1/100=0.01, multiply it by 100% and you get 1%.

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4 years ago

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If there are 180 grams of radioactive material with a half-life (decrease by half or 50%) of 1 hour, how much of the radioactive

Alexeev081 [22]

Answer:

After 3 hours there is left 22.5 grams of radioactive material.

Step-by-step explanation:

We can calculate the mass of radioactive material remaining after 3 hours, by using the decay equation:

$N_{t} = N_{0}*e^{-\lambda t}$ (1)

Where:

$N_{0}$ : is the initial mass = 180 g

$N_{t}$ : is the remaining mass after time t

λ: is the decay constant

The decay constant is given by:

$\lambda = \frac{ln(2)}{t_{1/2}}$

Where $t_{1/2}$ = 1 h.

By entering λ into equation (1) we hve:

$N_{t} = N_{0}*e^{-\frac{ln(2)}{t_{1/2}} t}$

$N_{t} = 180 g*e^{-\frac{ln(2)}{1 h} 3 h} = 22.5 g$

Therefore, after 3 hours there is left 22.5 grams of radioactive material.

I hope it helps you!

3 0

3 years ago