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Nady [450]
3 years ago
6

How do I solve this? (3^0y)^2x2(xy)^0

Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

(y ^2 ) (x ^2)

Step-by-step explanation:

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Look at this equation.
harkovskaia [24]

Answer:

3

Step-by-step explanation:

hey so we need to make the equations equal to one another for it to have infinitely many solutions

1)distribute the 3

3x+3=3x+_

looking at this we can concur that the missing number is 3. You can check by plugging in the 3 into the equation.

so

3x+3=3x+3

this is true, so 3 is the answer

hope this helps!

5 0
4 years ago
Read 2 more answers
Evaluate 1 5y+ 1 10 when y= 1 2.
pychu [463]

Answer:

290

Step-by-step explanation:

15(12)+110

290

8 0
3 years ago
Read 2 more answers
50+t=(3/2)<br><br> 50=(3/2)t-t<br><br> 50=(1/2)t <br><br> 100 =t <br><br> Where does 1/2 come from
mihalych1998 [28]
You are welcome
--------------------------

5 0
4 years ago
4cos^2(x)-7cos(x)+3<br> Please help and explain how you did it :)
dangina [55]

I assume you're asked to solve

4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0

Factor the left side:

(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0

Then either

4 cos(<em>x</em>) - 3 = 0   <u>or</u>   cos(<em>x</em>) - 1 = 0

cos(<em>x</em>) = 3/4   <u>or</u>   cos(<em>x</em>) = 1

From the first case, we get

<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em>  <u>or</u>   <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>

and from the second,

<em>x</em> = <em>nπ</em>

where <em>n</em> is any integer.

7 0
3 years ago
Mary has $2,300. She has decided that she will withdraw a fixed whole-dollar amount of money every month of the year. The fixed
Brrunno [24]

Given : Mary has $2300

Given : Mary decides to withdraw a fixed amount of money every month of the Year.

I'm Solving this Question by Verification of the Given Options

Let us Assume, She Withdraws a fixed amount of $190 every Month

⇒ The Amount she has withdrawn in a year = (190 × 12) = $2280

⇒ The Amount left over will be : (2300 - 2280) = $20

But, we can see that there is no $20 among the 2nd Blank Options. So, This Fixed amount of money cannot be the Answer.

Let us Assume, She Withdraws a fixed amount of $181 every Month

⇒ The Amount she has withdrawn in a year = (181 × 12) = $2172

⇒ The Amount left over will be : (2300 - 2172) = $128

But, we can see that there is no $128 among the 2nd Blank Options. So, This Fixed amount of money cannot be the Answer.

Let us Assume, She Withdraws a fixed amount of $180 every Month

⇒ The Amount she has withdrawn in a year = (180 × 12) = $2160

⇒ The Amount left over will be : (2300 - 2160) = $140

But, we can see that there is no $140 among the 2nd Blank Options. So, This Fixed amount of money cannot be the Answer.

Let us Assume, She Withdraws a fixed amount of $191 every Month

⇒ The Amount she has withdrawn in a year = (191 × 12) = $2292

⇒ The Amount left over will be : (2300 - 2292) = $8

We can see that there is a $8 among the 2nd Blank Options. So, This Fixed amount of money is the Answer.

The Fixed whole-dollar amount of money she takes from her account every month is $191 and she'll have 8 left over.

First Blank : $191

Second Blank : $8

4 0
3 years ago
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