Tahmid has 96 figures, Sandeep has 1/3 of it so
96(1/3) = 96/3 = 32
Sandeep has 32 figures
Tahmid 96 ; Sandeep 32
How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give.
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each.
Let's turn these into decimals.
so, 10.
0.75
0.50=1/2
0.40
0.20=1/5
In order from least to greatest, these would be:
0.2, 0.4, 0.5, 0.75, 10
The solution of the inequality is -8 ≥ b, and the correct graph is the one in option D.
"number line with a closed circle plotted at negative eight and arrow pointing left."
<h3>
How to solve the inequality?</h3>
Here we have the inequality:
-0.8*b + 2.3 ≥ 8.7
And we want to solve this, to do so, we need to isolate the variable b in one of the sides of the inequality.
-0.8*b + 2.3 ≥ 8.7
2.3 - 8.7 ≥ 0.8*b
-6.4 ≥ 0.8*b
-6.4/0.8 ≥ b
-8 ≥ b
So the solution is the set of all numbers equal to or smaller than -8, then the correct graph will be the one described by D.
Learn more about inequalities:
brainly.com/question/24372553
#SPJ1
Answer:
As per the statement:
Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.
Let H represents Hawick , A represents Abbotsford and K represents Kelso
See the diagram as shown below:
Distance of AH = 15 miles
Distance of AK = 17 miles.
We have to find the distance HK:
Using Pythagoras theorem;
then;
or
miles.
Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles
Answer;
They are 3 terms
The terms are the numbers and the variables separated by the minus sign and the plus sign
