1 2/3 + 1/8 Can you help pls Nowww pls

Mathematics

2 answers:

Likurg_2 [28]3 years ago

7 0

Answer:

Step-by-step explanation:

43/24

1 19/24

oksian1 [2.3K]3 years ago

5 0

Answer: 43/24

you but 1 2/3 as 5/ 3 then times the numerator and denominator by 8 and you get 40/24 for 1/8 you times the numerator and denominator by 3 and get 3/24 then you add the numerators in 40/23 and 3/24 and get 43/24

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Last choice says a over b but can someone please help me I am so lost need help ASAP

soldi70 [24.7K]

O(0,0) and A(a,b)

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Answer is the first one

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6 0

4 years ago

Read 2 more answers

Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)

timama [110]

<h3>Answer: c = 7/4</h3>

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Work Shown:

Compute the function value at the endpoints

$f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\$

With a = -5 and b = 4, we have

$f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\$

So,

$f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\$

Use algebra to solve for c

$-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\$