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Ilia_Sergeevich [38]

3 years ago

7

a group of hikers buy 8 bags of trail mix.each nag contains 3 1\2 cups of trail mix.the trail mix is shared evenly among 12 hike

rs.how many cups of trail mix will each hiker get?

1 answer:

Troyanec [42]3 years ago

8 0

2 1/3 cup of trail mix per hiker.

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14 What value of x makes this equation true?<br> 12x - 15 = 6 - 3x<br><br> Plsss help me and hurry

rodikova [14]

Answer:

1.4

Step-by-step explanation:

12x+3x=15+6

15x=21

X=21/15

X=7/5 or 1.4

5 0

2 years ago

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

2 years ago

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Will give brainliest! Probability

alex41 [277]

Answer:

1/49

Step-by-step explanation:

You wrote the problem correctly. You just needed to multiply instead of add.

1/7*1/7=1/49

So the answer is 1/49.

3 0

3 years ago

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Solve the equation <br><br> 3x-5< 8x-1/2<br><br> x+7≤ 4x+1

vladimir1956 [14]

This is all I got. Hope this helps:

6 0

1 year ago

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Find the vertex of this parabola.<br><br><br><br> y = -2x2 + 4x + 12

STatiana [176]

For this case we have the following equation:
$y = -2x ^ 2 + 4x + 12
$
Deriving we have:
$y = -2x ^ 2 + 4x + 12

y '= -4x + 4$
We match zero:
$-4x + 4 = 0
$
We clear the value of x:
$4x = 4

x = 4/4

x = 1$
Then, we substitute the value of x in the equation of the parabola:
$y = -2 (1) ^ 2 + 4 (1) + 12

y = -2 + 4 + 12

y = 14$
Thus, the vertex of the parabola is the ordered pair:
$(x, y) = (1, 14)$
Answer:
The vertice is:
$(x, y) = (1, 14)$

3 0

3 years ago