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Alja [10]
3 years ago
13

There are 144 microscopes in boxes at a school. each box has 24 microscopes which equation could be used to find b, the number o

f boxes of microscopes at this school
A. 24+144= b
B. 144-b= 24
C. B divided by 24= 144
D. 24 x b= 144
Mathematics
1 answer:
garik1379 [7]3 years ago
8 0
D ...................
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If an item is 1/3 off, to calculate the final price simply divide the original price by 3. true or false
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False..

if it was asking for 1/3 of the original price, it would be true
but 1/3 off....means u are paying 2/3...so u would multiply the original price by 2, then divide by 3...or u would take the original price and subtract 1/3 * the original price
5 0
4 years ago
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Solve for h in this equation: 12=1/2h (2 1)
Murljashka [212]
Hello there.

<span>Solve for h in this equation: 12=1/2h (2 1)

h=8/7</span>
6 0
3 years ago
Find the next three terms in the sequence.<br> 3, 6, 12, 24,...
Sauron [17]

Answer:

48,96,192

Step-by-step explanation:

We see that each term is twice of the previous term.  Using this principle, we get the next three terms, which are 48,96,192.

3 0
3 years ago
Solve for m∠WUV if m∠TUV= 100 and m∠TUW = 60.
Veronika [31]

Answer:

20

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100 + 60 = 160

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6 0
3 years ago
Susan invests $Z at the end of each year for seven years at an annual effective interest rate of 5%. The interest credited at th
aleksley [76]

Answer:

2.02955

Step-by-step explanation:

Given that:

Susan invests $Z as each year ends for seven years.

So we assume that Z = 1

Susan's accrued value comprises $7 invested each year at a 6 percent annual effective rate.

The cashflow interest:

The cashflow of Susan interest payments are:

Payments   Time

0                     1

0.05               2

2(0.05)           3

3(0.05)           4

4(0.05)            5

5(0.05)            6

6(0.05)            7

The accumulated value of this cash flow is:

(0.05)I_{6\%} = (0.05) \dfrac{((1+0.06)_{6\%} - 6)}{0.06} \\ \\ \implies 1.1653

So Susan accumulated values is:

X = 7 + 1.1653

X = 8.1653

Lori's accumulated value is $14, which she has set aside to plan her cash flow for interest.

The cashflow of Lori interest payments are;

Payments    0     0.025     2(0.025)       3(0.025)    .........   13(0.025)

Time             1        2              3                    4            ..........  14

The accumulated value of cash flow is:

(0.025 )(I)_{3\%} =(0.025) \dfrac{(1+0.03)_{3\%}-13}{0.03}\\ \\= 2.5719

Now, Lori's accumulated value is:

Y = 14 + 2.5719

Y = 16.5719

Since; Susan value X = 8.1653

Lori's value Y = 16.5719

∴

\dfrac{Y}{X}= \dfrac{16.5719}{8.1653}

= 2.02955

7 0
3 years ago
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