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Scorpion4ik [409]
3 years ago
15

I am completely stumped...

Mathematics
1 answer:
Nana76 [90]3 years ago
7 0

Answer:

x=25\sqrt{2}

Step-by-step explanation:

the hypotenuse is equal to a leg times the square root of 2. which means to find the leg with the hyp given. you take \frac{50}{\sqrt{2} } which then translates to 50 root 2/2=x  therefore 25\sqrt{2}

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Step 1: (6×10^3) ÷ (2×10^2)
Nookie1986 [14]

Answer:

Error is in between the second and third step

the exponents must be subtracted

Step-by-step explanation:

8 0
3 years ago
Graph each circle given below right the center and the radius of each circle
Paraphin [41]

Answer:

Center: (-1,8)

Radius: 1

The graph is attached.

Step-by-step explanation:

The equation of the circle has the form:

(x -h)^{2}+(y-k)^{2}=r^{2}

Where (h,k) is the  point of the center of the circle and r is the radius of the circle.

The equation given in the problem is

(x +1)^{2}+(y-8)^{2}=1

 Therefore:

h=-1

k=8

 Then, the center is (-1,8) and radius is 1.

You can graph the circle with its center at the (-1,8) and a radius of 1 as you can see in the figure attached.

4 0
4 years ago
Read 2 more answers
Which is one of the transformations applied to the graph of f(x) = x2 to change it into the graph of g(x) = 9x? – 36X?
matrenka [14]

Answer: C. The graph of f(x)= x2 is shifted down 36 units

Step-by-step explanation:

6 0
3 years ago
Find the length of BC. <br> A.) 14<br> B.) 9<br> C.) 2<br> D.) 3
Vera_Pavlovna [14]

Answer:

A) 14

Step-by-step explanation:

BC is congruent to DC in saying this you can plug the equations to each other and solve for y and then put its back into the equation for BC to get the length.

3y+5=5y-1

subtract 3y from both sides --> 5=2y-1

add 1 to both sides --> 6=2y

now get y alone, divide by 2 by both side --> y=3

plug y in back to 5y-1 --> 5x3-1

15-1

BC = 14

7 0
3 years ago
Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated
koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.


With this, you will need to use the distance formula, \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, on XY, YZ, and ZX.



XY: \sqrt{(3-1)^2+(1-6)^2}


Firstly, solve inside the parentheses: \sqrt{(2)^2+(-5)^2}


Next, solve the exponents: \sqrt{4+25}


Next, solve the addition, and XY's distance will be √29



(The process is the same with the other 2 sides, so I'll go through them real quickly)


YZ:

\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}



ZX:

\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}



Now that we got the 3 sides, we can add them up: \sqrt{29}+\sqrt{13} +\sqrt{34} =14.8


In short, your answer is 14.8, or the second option.

8 0
3 years ago
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