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ziro4ka [17]
3 years ago
10

Write two numbers which his greatest common divisor is 210 and to be between 10000 and 11000

Mathematics
1 answer:
torisob [31]3 years ago
3 0

Answer:

  10080, 10290

Step-by-step explanation:

The multipliers of 210 required will be mutually prime integers that satisfy ...

  10000 ≤ 210n ≤ 11000

  47.61 ≤ n ≤ 52.38

That is, you want a pair of integers, each between 48 and 52, that have no common factors. Possibilities include ...

  (48, 49), (49, 50), (49, 51), (49, 52), (50, 51), (51, 52)

For the above numbers, we have chosen ...

  48×210 = 10,080

  49×210 = 10,290

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Answer:

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Step-by-step explanation:

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Substituting,

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3 years ago
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4 years ago
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never [62]

Answer:

It was difficult reading the question, as written.  Check my assumptions.

Step-by-step explanation:

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