I believe it is 4^-5
2^6 (<span>2^-4/ 2^7)
=2^6(2^-4-+7)
=</span>2^6(2^-11)
=4^6-11
=4^-5
Answer: Algebraic linear expression
Step-by-step explanation:
An algebraic expression in mathematics is an expression built up from integer constants with
unknown variables, and the algebraic operations. For example, 6x² − 2xy + 20 is an algebraic expression which is quadratic in nature.
The general formular for algebraic linear expression is Y - MX - C
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Hi!
If she worked 18 hours last week and 20 hours this week, then she worked 38 hours in total, because 18 + 20 = 38.
If she earns $6 per hour, and she worked for 38 hours, then she got 38 sets of 6, which you can find the answer to by multiplying 38 and 6.
This is essentially 6 + 6 + 6 +...
38 * 6 = $228
So she earned $228 these two weeks.
Hope this helped!
