Answer:
polygon klhij is congruent to polygon vwstu
Step-by-step explanation:
Answer: 90
Step-by-step explanation:
set: {1, 2, 3, 4, 5, 6, 7} = 7 numbers | 3 even
no element may be used more than once in a number = distinct elements
and the number must be even = must finish with a even number.
This way, we should start with the last number, which we have 3 possibilities.
Since we have 7 numbers in total, we have 6 options for the first one and then 5 options for the second one.
So, we have 6.5.3 = 90
Answer:
24m - 28
Step-by-step explanation:
Given the expression (6m−7)⋅4, we are to simplify it. Using the distributive law;
A(B+C) = AB + AC [A is distributed over B and C]
For the expression (6m−7)⋅4, we will distribute 4 over 6m and -7 as shown;
(6m−7)⋅4 = 4(6m) - 4(7)
(6m−7)⋅4 = 24m - 28
Hence (6m−7)⋅4 = 24m - 28
Looking at the image of the cube you can see the outer edges would have paint on 2 sides and the corners would have paint on n3 sides.
The only ones with paint on one pace is the center cubes.
There are 6 sides to a cube and there would be 6 center pieces.
Answer: 6
Answer:
GCF is 4
Step-by-step explanation:
The factors of 20 are: 1, 2, 4, 5, 10, 20
The factors of 28 are: 1, 2, 4, 7, 14, 28
Then the greatest common factor is 4.
