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Dafna11 [192]
3 years ago
10

Select the correct answer from each drop-down menu. Which two factors do ergonomic principles consider a part of a job? Ergonomi

c principles consider (physical stress, mental stress, or social stress) and (traveling factors, relationship factors, or environmental factors) Pls answer quickly I have a Mastery test and my brain is a little rusty so pls help me! I would really appreciate it and thank you so much in advance and have a good day! Btw, I'll give 55 points if it's answered correctly :D​
Computers and Technology
1 answer:
Rudiy273 years ago
4 0

Answer:mental stress

Explanation:

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You should periodically perform basic computer maintenance on your computer.<br> True<br> False
kotegsom [21]

Answer:

that's true after some period of time it's necessary

8 0
2 years ago
Read 2 more answers
It is a well-researched fact that men in a restroom generally prefer to maximizetheir distance from already occupied stalls, by
Artyom0805 [142]

Answer:

The code below addresses the problem statement with appropriate comments for explanation.

Explanation:

public class Stall

{

public static void main(String[] args)

{

boolean[] arr = new boolean[10];

while(hasFreeSpots(arr))   // as long as there is a free slot

{

arr[position(arr)] = true;  

// position(arr) gets the position of slot a person would most likely enter at(view problem statement)

// setting that position true(position occupied) by arr[position(arr)]

System.out.println(stallView(arr));   // printing current state of the stall using 'X' and '_'

}

}

/**

* Find the empty position that is in the middle of the sub-array of largest group of empty spots

* @param arr an array of boolean values

* @return returns an an integer value. Optimal position to be occupied.

*/

public static int position(boolean[] arr)

{

int first = 0;   // first stores the starting position of "longest sequence of unoccupied places"

int last = 0;   // last stores the ending position of "longest sequence of unoccupied places"

int temp1 = 0;   // temp1 stores the starting position of "current sequence of unoccupied places"

int temp2 = 0; // temp2 stores the ending position of "current sequence of unoccupied places"

 

for(int i = 0; i < arr.length; i++)   // for each slot in the Stall

{    

if(!arr[i]) // if slot i is not occupied

{    

temp1 = i;   // store starting position of "current sequence of unoccupied places" in temp1

while(i < arr.length && !arr[i] )   // if i is a valid index and as long as this slot is not occupied increment i

{

i++;

}

// we break out of the loop either if i is invalid index(reached end of the array)

// or if the slot is occupied by a person already

temp2 = i;   // store ending position of "current sequence of unoccupied places" in temp2

if(Math.abs(first - last) < Math.abs(temp1 - temp2))

  // if current sequence is longer than longest sequence, update it

{

first = temp1;

last = temp2;    

}

}

}

return (first + last) / 2;   // return middle index of first and last

}

/**

* Checks if there are empty spots in an array, basically checks if there is a false boolean value

* thats representing an empty spot in an array

* @param arr the input array, of boolean values

* @return returns a boolean value, true if there are false elements inside the array

*/

public static boolean hasFreeSpots(boolean[] arr)

{

boolean rtn = true;   // initializing rtn to 'true'

for(int i = 0; i < arr.length; i++)   // for every slot in the Stall

{

if(!arr[i]){rtn = false;}   // sets rtn to false if a free spot found

}

return !rtn;   // returns true if a free spot found and returns false if no free spot found

}

/**

* X for true, _ for false. Representing occupied(X) and free stalls(_)

* @param arr a boolean array

* @return returns a string representation if the input

*/

public static String stallView(boolean[] arr)

{

String str = "";       // initializing str to be an empty String

for(int i = 0; i < arr.length; i++)   // for every slot in Stall

{

if(arr[i]){str += " X";}   // Add X to str if slot is occupied

else {str += " _";}           // prints _ to str if slot not occupied

}

return str;       // return str(pictorial representation of Stall with 'X', '_')

}

}

7 0
3 years ago
Convert 192.16.3.1 to a Binary number
jenyasd209 [6]
Converting a decimal number into binary would be:

192/2= 96   remainder=0  
96/2= 48    remainder=0
48/2=24     remainder=0
24/2=12      remainder=0
12/2=6        remainder=0
6/2=3         remainder=0
3/2=1          remainder=1
1/2= 0         remainder=1
The binary number would be: 11 00 00 00

For 16
16/2=8     remainder=0
8/2=4      remainder=0
4/2=2       remainder=0
2/2=1         remainder=0
1/2= 0         remainder=1
The binary would be: 00 01 00 00

For 3
3/2=1       remainder=1
1/2= 0         remainder=1
The binary would be: 00 00 00 11

For 1
1/2= 0         remainder=1
The binary would be: 00 00 00 01

The binary number would be:  
11000000.00010000.00000011.00000001
5 0
3 years ago
Needd helppp asappp testing rn
Margarita [4]

Answer: second choice is the best

Explanation:

Because even choice one is inside 2 while 3&4 are false

7 0
2 years ago
Categorize the e-publications as a means of networking or as a storehouse of resources
stealth61 [152]

Answer:

 The answer is "E-book, E-portfolio, and website ".

Explanation:

e-publications define as a method of connectivity are sites online besides the un-mail community newsgroup blog. It defines as a category of means, which storehouse with resource base are E-book, E-portfolio, and website.

  • On the website, it can be classified as both connectivity and storage facility of information.  
  • On the website when network security like yahoo website only as a storage area of resource development website to access or download PDF files.
8 0
3 years ago
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