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Sonja [21]
3 years ago
7

Which of the following shows a list of Big-Oh running times in order from slowest to fastest?

Computers and Technology
2 answers:
Irina18 [472]3 years ago
8 0

Answer: I pretty much agree with him.

Explanation:

Rufina [12.5K]3 years ago
5 0

Answer:

O(N!), O(2N), O(N2), O(N), O(logN)

Explanation:

N! grows faster than any exponential functions, leave alone polynomials and logarithm. so O( N! ) would be slowest.

2^N would be bigger than N². Any exponential functions are slower than polynomial. So O( 2^N ) is next slowest.

Rest of them should be easier.

N² is slower than N and N is slower than logN as you can check in a graphing calculator.

NOTE: It is just nitpick but big-Oh is not necessary about speed / running time ( many programmers treat it like that anyway ) but rather how the time taken for an algorithm increase as the size of the input increases. Subtle difference.

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Here is a Test Code segment:
Tju [1.3M]
Here's the best answer I can give you, but bear with me.
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3 years ago
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coldgirl [10]

1. Acts of human error

<u>Explanation:</u>

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